Below length is square root of 2*3
hypotenuse is 2
Answer:
c(x)=(x+3)^2+5
Step-by-step explanation:
To complete the square, the same value needs to be added to both sides.
So, to complete the square x^2+6x+9=(x+3)^2 add 9 to the expression
C(x) =x^2 +6x + 9 + 14
Since 9 was added to the right-hand side also add 9 to the left-hand side
C(x) +9= x^2 +6x + 9 + 14
Using a^2 + 2ab + b^2=(a+b)^2, factor the expression
C(x)+9= (x+3)^2 +14
Move constant to the right-hand side and change its sign
C(x)=(x+3)^2 +14 - 9
Subtract the numbers
C(x)= (x+3)^2 +5
Answer:
Below.
Step-by-step explanation:
f) (a + b)^3 - 4(a + b)^2
The (a+ b)^2 can be taken out to give:
= (a + b)^2(a + b - 4)
= (a + b)(a + b)(a + b - 4).
g) 3x(x - y) - 6(-x + y)
= 3x( x - y) + 6(x - y)
= (3x + 6)(x - y)
= 3(x + 2)(x - y).
h) (6a - 5b)(c - d) + (3a + 4b)(d - c)
= (6a - 5b)(c - d) + (-3a - 4b)(c - d)
= -(c - d)(6a - 5b)(3a + 4b).
i) -3d(-9a - 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b).
= (3d + 2c)(9a + 2b).
j) a^2b^3(2a + 1) - 6ab^2(-1 - 2a)
= a^2b^3(2a + 1) + 6ab^2(2a + 1)
= (2a + 1)( a^2b^3 + 6ab^2)
The GCF of a^2b^3 and 6ab^2 is ab^2, so we have:
(2a + 1)ab^2(ab + 6)
= ab^2(ab + 6)(2a + 1).
X=12 because you would sub the 3 on both sides
