Question

two points on the line are (-10,1) and (5,-5).if the coordinate of another point on the line is -3,what is the x-coordinate?​

Answer 1

Answer:

x-coordinate = 0

Step-by-step explanation:

(-10,1) , (5,-5)

m = (y₂ - y₁)/(x₂ - x₁) = ( -5 - 1 ) / ( 5 - [-10] )

   = -6 / ( 5 + 10)

    = -6/15 = -2/5

y - y₁  = m (x - x₁)

y - 1 = (-2/5) ( x - [-10] )

y - 1 = (-2/5) ( x + 10 )

5 * (y -1)  = -2 (x + 10)

5y - 5 = -2x -20

2x + 20 + 5y  -5 = 0

2x + 5y + 15 = 0

Another point (a, -3) in on this line

2 * a + 5 * (-3) = -15

          2a -15    = -15

                  2a  = -15 +15

                 2a =  0

                    a = 0

x-coordinate = 0