two points on the line are (-10,1) and (5,-5).if the coordinate of another point on the line is -3,what is the x-coordinate?
1 answer:
Answer:
x-coordinate = 0
Step-by-step explanation:
(-10,1) , (5,-5)
m = (y₂ - y₁)/(x₂ - x₁) = ( -5 - 1 ) / ( 5 - [-10] )
= -6 / ( 5 + 10)
= -6/15 = -2/5
y - y₁ = m (x - x₁)
y - 1 = (-2/5) ( x - [-10] )
y - 1 = (-2/5) ( x + 10 )
5 * (y -1) = -2 (x + 10)
5y - 5 = -2x -20
2x + 20 + 5y -5 = 0
2x + 5y + 15 = 0
Another point (a, -3) in on this line
2 * a + 5 * (-3) = -15
2a -15 = -15
2a = -15 +15
2a = 0
a = 0
x-coordinate = 0
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Step-by-step explanation:
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