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Sever21 [200]
3 years ago
14

Identify the decimals labeled with the letters A, B, and C on the scale below. Letter A represents the decimal Letter B represen

ts the decimal Letter C represents the decimal

Mathematics
1 answer:
Yuliya22 [10]3 years ago
8 0

10 divisions between $389$ and $390$ so each division is $\frac{390-389}{10}=0.1$

A is 8 division from $389$, so, A is $389+8\times 0.1=389.8$

similarly, C is one division behind $389$ so it is $389-1\times 0.1=388.9$

and B is $390.3$

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4%

Step-by-step explanation:

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PLEASE HELP!!! I need an urgent answer and I'll give brainiest just please answer this easy question!
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Evaluate [(30+6)-3^2] ÷ by 9·2
kow [346]

Answer:

PEMDAS

[(30+6)-3^2] ÷ by 9·2

[(30+6)-9] ÷ by 9·2

[(36)-9] ÷ by 9·2

(27) ÷ by 9·2

Division comes first in this equation. Multiplication & Division goes from left to right when using PEMDAS. Same thing goes for Addition & Subtraction.

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Hopefully that made sense!

Step-by-step explanation:

8 0
3 years ago
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Complete the following statements to prove that ∠IKL and ∠JLD are supplementary angles. It is given that ∠EIJ ≅ ∠GJI. Also, ∠EIJ
Dima020 [189]

Answer:

1st blank: substitution property of equality

2nd blank: linear pair theorem

3rd blank: substitution property of equality

Step-by-step explanation:

<u>1st blank</u>

∠EIJ ≅ ∠GJI (eq. 1)

∠EIJ ≅ ∠IKL (eq. 2)

∠GJI ≅ ∠JLK (eq. 3)

Substituting eq. 3 into eq. 1:

∠EIJ ≅ ∠JLK

and then, substituting eq. 2:

∠IKL ≅ ∠JLK

which means that m∠IKL = m∠JLK

<u>2nd blank</u>

The Linear Pair Theorem states that two angles that form a linear pair are supplementary

<u>3rd blank</u>

m∠JLK + m∠JLD = 180°

Substituting with the previous result:

m∠IKL + m∠JLD = 180°

6 0
3 years ago
The green line below
kenny6666 [7]

Answer:

B, C, D, & E

Step-by-step explanation:

All lines intersect the x axis and y axis so we know B and D are correct. All graphs are in the xy plane unless i (\sqrt{-1}) is involved, or C. It crosses the center (origin) of the entire plane so it crosses the origin, or E.

3 0
3 years ago
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