The acceleration of the object will be 10 m/s²
Step-by-step explanation:
Direct variation is a relationship between two variables that can be expressed by an equation in which one variable is equal to a constant times the other
- If y varies directly with x, then y ∝ x
- y = k x, where k is the constant of variation
For a moving object, the force acting on the object varies directly with the object's acceleration.
Assume that the force is F and the acceleration is a
∵ F ∝ a
∴ F = k a
∵ F = 20 newtons
∵ a = 4 m/s²
- Substitute these values in the equation above to find k
∵ 20 = k (4)
∴ 20 = 4 k
- Divide both sides by 4
∴ k = 5
- Substitute the value of k in the equation
∴ F = 5 a ⇒ equation of variation
∵ F = 50 Newtons
∵ F = 5 a
∴ 50 = 5 a
- Divide both sides by 5
∴ 10 = a
∴ a = 10 m/s²
The acceleration of the object will be 10 m/s²
Learn more:
You can learn more about variation in brainly.com/question/10708697
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It’s 2/15
It’s just 2x1 and 3x5
Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
