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3 years ago

Please help me with this

Mathematics

1 answer:

Dvinal [7]3 years ago

8 0

Answer:

a. E = {1, 2, 3, 4, 5, 6, 7, 8}
b. A ∩ B = {2, 3}
c. A ∪ B = {1, 2, 3, 4, 5, 7, 8}

Step-by-step explanation:

Locate the designated space on the diagram and list all the numbers in it.

a. E = {1, 2, 3, 4, 5, 6, 7, 8} . . . . all numbers in the rectangle

b. A ∩ B = {2, 3} . . . . where the circles overlap

c. A ∪ B = {1, 2, 3, 4, 5, 7, 8} . . . . only 6 is outside the circles

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Gail has $5,500 that she wants to put in a new savings account. She is

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Step-by-step explanation:

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3 years ago

the 22 students bought a Valentine's presents they purchased 2 dozen for 22.95$ per and a box of chocolates for 13.45$ they spli

irina [24]

Answer:

I think the answer is b

Step-by-step explanation:

I think its b because, $22.95 plus $13.45 equals $36.40. And divide that by 22, and get $1.60 rounded is $2.00. I hope this can help.

3 0

3 years ago

Please help and explain please !!!!!!

Vaselesa [24]

21. 2•2=4
24. 3.4•2.4=5.8
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Hope this helps!

5 0

4 years ago

Read 2 more answers

Find the center and the radius of the circle x2 + y2 − 2x + 6y − 6 = 0.

asambeis [7]

x 2 + y 2 + a x + b y = c

x2 + y2 − 2x + 6y − 6 = 0

Steps:

x^2 + y^2 - 2x + 6y - 6 = 0

(x - 1)^2 + (y - (-3)^2=4^2

Which means...

Center = (1,-3)

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Or option B

6 0

1 year ago

Twenty identical looking packets of white power are such that 15 contain cocaine and 5 do not. Four packets were randomly select

xxMikexx [17]

Answer:

The probability of selecting randomly 6 packets such that the first 4 contain cocaine and 2 not is 0.3522.

Step-by-step explanation:

Probabilities of selecting 4 packets with the ilegal substance:

$(\frac{15}{4})\\$ = $\frac{15!}{4!(15-4)!}$

Combinassions possible= 1365

Probabilities of selecting 2 packets with white powder:

$(\frac{5}{2})$ = $\frac{5!}{2!(5-2)!}$

Combinations possible= 10

Probabilities of selecting 6 packets from the totality of them:

$(\frac{20}{6})$ = $\frac{20!}{6!(20-6)!}$

Combinations possible= 38760

The probability of picking 4 with the substance and 2 with only white powder is:

$\frac{(15ncr4)(5ncr2)}{(20ncr6)}$ = 0.3522

I hope this answer helps you.

6 0

3 years ago