How many moles of N₂O₅ are produced when 3.00g of O₂ react completely in the following equation? 2N₂ + 5O₂ → 2N₂O₅ A. 0.0375 B.

Question

4 years ago

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0.0750 C. 0.234 D. 0.469

1 answer:

a_sh-v [17] · Answer 1 · 2022-01-15T01:40:56+03:00

4 0

Answer: A. 0.0375

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} O_2=\frac{3.00g}{32g/mol}=0.094moles$

$2N_2+5O_2(g)\rightarrow 2N_2O_5$

According to stoichiometry :

As 5 moles of $O_2$ give = 2 moles of $N_2O_5$

Thus 0.094 moles of $O_2$ give = $\frac{2}{5}\times 0.094=0.0375moles$ of $N_2O_5$

Thus 0.0375 moles of $N_2O_5$ will be produced when 3.00g of O₂ react completely