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3 years ago

Properties of iron, barium, and phosphorus. Explain why nails are made of iron but they are never made of barium or phosphorus.

Chemistry

1 answer:

bearhunter [10]3 years ago

3 0

Nails are made up of iron not of phosphorus and barium.

As both phosphorous and barium are relatively weaker than iron ,phosphorus breaks easily and barium is also fairly weak. Iron nails are already also not that strong, but their weight and strength are sufficient.

So the nails are made up of iron.

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What two properties do all forces have?

Ksenya-84 [330]

The two properties all forces have are: Directionand magnitude or Size

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4 years ago

Read 2 more answers

Predict the density of acetylene gas (C2H2) at 0.910 atm and 20oC.

zhuklara [117]

Answer:

d = 0.98 g/L

Explanation:

Given data:

Density of acetylene = ?

Pressure = 0.910 atm

Temperature = 20°C (20+273 = 293 K)

Solution:

Formula:

PM = dRT

R = general gas constant = 0.0821 atm.L/mol.K

M = molecular mass = 26.04 g/mol

0.910 atm × 26.04 g/mol = d × 0.0821 atm.L/mol.K×293 K

23.7 atm.g/mol = d × 24.1 atm.L/mol

d = 23.7 atm.g/mol / 24.1 atm.L/mol

d = 0.98 g/L

6 0

3 years ago

Determine the empirical formula of a compound having the following percent composition by mass: K: 24.74%; Mn: 34.76%; O: 40.50%

Dovator [93]

Answer: The empirical formula of the compound is $KMnO_4$

Explanation:

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Let the mass of the compound be 100 g

Given values:

% of K = 24.7%

% of Mn = 34.76%

% of O = 40.50%

Mass of K = 24.7 g

Mass of Mn = 34.76 g

Mass of O = 40.50 g

To calculate the empirical formula of a compound, few steps need to be followed:

Step 1: Calculating the number of moles of each element

We know:

Molar mass of K = 39.10 g/mol

Molar mass of Mn = 54.94 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of K}=\frac{24.7g}{39.10g/mol}=0.632 mol$

$\text{Moles of Mn}=\frac{34.76g}{54.94g/mol}=0.633 mol$

$\text{Moles of O}=\frac{40.50g}{16g/mol}=2.53 mol$

Step 2: Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 0.632 moles

$\text{Mole fraction of K}=\frac{0.632}{0.632}=1$

$\text{Mole fraction of Mn}=\frac{0.633}{0.632}=1$

$\text{Mole fraction of O}=\frac{2.53}{0.632}=4$

Step 3: Writing the mole fraction as the subscripts of each of the element

The empirical formula of the compound becomes $K_1Mn_1O_4=KMnO_4$

Hence, the empirical formula of the compound is $KMnO_4$

4 0

3 years ago

Correctly complete the following about how light waves are arranged on the electromagnetic spectrum. The _____ of the waves ____

MrRa [10]

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3 years ago

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nalin [4]

We should change it to mol and then ×Number of Avogadro

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2 years ago