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3 years ago

16 Which two gases can not be broken down by chemical means?(1) CO and He (3) Xe and He

1 answer:

4 0

The answer is (2) CO and NH3. The chemical reaction can only break down chemical bonds between atoms inside the molecule. The He and Xe is consists of one atom only, so they can not be broken down by chemical means.

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Which of the following statements about compounds is true?

Katarina [22]

Explanation:

A and D is the answer

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3 years ago

A student adds a rectangular block of mass 26.10 g to a graduated cylinder initially filled with 40.1 mL of water, but some wate

Amiraneli [1.4K]

Answer:

The splash cause the volume of the block to be too high

Explanation:

This is because, from the previous measurement made by the student, the volume of the block is 5.7ml higher.

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2 years ago

Which of Newton's laws introduces the concepts of action/reaction forces?

viktelen [127]

It would be D.3

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3 years ago

Read 2 more answers

If ch4 and c4h8 are released simultaneously at ends of a 50.0cm long glass tube, at what distance from the left end of the tube

Keith_Richards [23]

Answer:

They meet at the distance of 32.5 cm

Explanation:

The rate of diffusion is inversely proportional to the molar mass of gases.

If diffusion is represented as d and mass of gases as M. Then , rate is given as:

$d=k\sqrt{\frac{1}{M}}$

For , two gases

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}$

First , Calculate the ,molar mass of each gas :

CH4 = 1 (mass of C) + 4(mass of H)

= 1(12)+4(1)

= 12 + 4 = 16 gram

M1 = 16 gram

C4H8 = 4(mass of C) + 8(Mass of H)

= 4(12) + 8(1)

= 48 + 8

M2 = 56 grams

d1 is diffusion of CH4

d2 = diffusion of C4H8

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{56}{16}$ }

$\frac{d_{1}}{d_{2}} = 1.87$

This means CH4 diffuse 1.87 times faster than C4H8

Now, the mathematical part

If velocity of C4H8 = 1 cm/sec , then velocity of CH4 = 1.87 cm/sec

v1 = 1.87 cm/sec

v2 = 1 cm/sec

Let both meet at time "t". If distance travelled by CH4(s1) = x , then remaining(s2) distance (50-x) is travelled by C4H8

(see the attached image)

$time =\frac{distance}{speed}$

since both meet at same time so t = constant.

$\frac{s1}{v1}=\frac{s2}{v2}$

$\frac{x}{1.87}\frac{50-x}{1.00}$

on solving for x we get,

x = 17.42 cm

from the other side the distance is (50 - x)

= 50 - 17.42 = 32.5 cm

7 0

3 years ago

5. If the reaction of carbon monoxide and oxygen gas in question 2

zheka24 [161]

Answer: The mass in grams is 514.8.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadros number}}$

given molecules = $7.03\times 10^{24}$

Putting in the values we get:

$\text{Number of moles}=\frac{7.03\times 10^{24}}{6.023\times 10^{23}}=11.7moles$

mass of $CO_2=moles\times {\text {Molar mass}}=11.7mol\times 44g/mol=514.8g$

The mass in grams is 514.8.

8 0

3 years ago