1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Greeley [361]
3 years ago
12

Predict the products of each of these reactions and write balanced complete ionic and net ionic equations for each. If no reacti

on occurs, write NOREACTION .
Part A : LiCl(aq)+AgNO3(aq)→

Express your answer as a complete ionic equation. Identify all of the phases in your answer. Enter noreaction if no reaction occurs.

Part B: Express your answer as a net ionic equation. Identify all of the phases in your answer. Enter noreaction if no reaction occurs.

Part C: H2SO4(aq)+Li2SO3(aq)→

Express your answer as a complete ionic equation. Identify all of the phases in your answer. Enter noreaction if no reaction occurs.

Part D: Express your answer as a net ionic equation. Identify all of the phases in your answer. Enter noreaction if no reaction occurs.

Part E: HClO4(aq)+Ca(OH)2(aq)→

Express your answer as a molecular equation. Identify all of the phases in your answer. Enter noreaction if no reaction occurs.

Part F: Cr(NO3)3(aq)+LiOH(aq)→

Express your answer as a complete ionic equation. Identify all of the phases in your answer. Enter noreaction if no precipitate is formed.

Part G:

Express your answer as a net ionic equation. Identify all of the phases in your answer. Enter noreaction if no precipitate is formed.

Part H: HCl(aq)+Hg2(NO3)2(aq)→

Express your answer as a complete ionic equation. Identify all of the phases in your answer. Enter noreaction if no precipitate is formed.

Part I: Express your answer as a net ionic equation. Identify all of the phases in your answer. Enter noreaction if no precipitate is formed.
Chemistry
1 answer:
Bumek [7]3 years ago
8 0

Answer:

Explanation:

Part A : LiCl(aq) + AgNO₃(aq)→

Chemical equation:

LiCl(aq) + AgNO₃(aq)  →  AgCl(s) + LiNO₃(aq)

Ionic equation:

Li⁺(aq)  + Cl⁻(aq) + Ag⁺(aq) + NO₃⁻(aq)  →  AgCl(s) + Li⁻(aq)  + NO⁻₃(aq)

Net ionic equation:

Cl⁻(aq) + Ag⁺(aq) →  AgCl(s)

C = H2SO4(aq)+Li2SO3(aq)→

Chemical equation:

H₂SO₄(aq) + Li₂SO₃(aq)  →  Li₂SO₄(aq) + SO₂(g) + H₂O(l)

Ionic equation:

2H⁺(aq)  + SO²⁻₄(aq) + 2Li⁺(aq)  + SO₃²⁻(aq)  →  2Li⁺ (aq) + SO₄²⁻(aq) + SO₂(g) + H₂O(l)

Net ionic equation:

2H⁺ + SO₃²⁻(aq)  →  SO₂(g) + H₂O(l)

Part E: HClO4(aq)+Ca(OH)2(aq)→

Chemical equation:

HClO₄(aq) + Ca(OH)₂(aq)  →  Ca(ClO₄)₂ (aq) + H₂O(l)

Balanced Chemical equation:

2HClO₄(aq) + Ca(OH)₂(aq)  →  Ca(ClO₄)₂ (aq) + 2H₂O(l)

Ionic equation:

2H⁺(aq) + 2ClO⁻₄(aq) + Ca²⁺(aq) + (OH)²⁻₂(aq)  →  Ca²⁺(aq) +(ClO₄)²⁻₂ (aq) + 2H₂O(l)

Net ionic equation:

2H⁺(aq) + (OH)²⁻₂(aq)  →  2H₂O(l)

Part F: Cr(NO3)3(aq)+LiOH(aq)→

Chemical equation:

Cr(NO₃)₃(aq) + LiOH (aq)  →   LiNO₃(aq) + Cr(OH)₃(s)

Balanced chemical equation;

Cr(NO₃)₃(aq) + 3LiOH (aq)  →   3LiNO₃(aq) + Cr(OH)₃(s)

Ionic equation:

Cr³⁺(aq) + 3NO₃⁻(aq) + 3Li⁺(aq) + 3OH⁻ (aq)  →   3Li⁺(aq) + 3NO⁻₃(aq) + Cr(OH)₃(s)

Net ionic equation:

Cr³⁺(aq) +  3OH⁻ (aq)  →    Cr(OH)₃(s)

Part H: HCl(aq)+Hg2(NO3)2(aq)→

Chemical equation:

HCl (aq) + Hg₂(NO₃)₂(aq)  → Hg₂Cl₂ (s) + HNO₃(aq)

Balanced chemical equation:

2HCl (aq) + Hg₂(NO₃)₂(aq)  → Hg₂Cl₂ (s) + 2HNO₃(aq)

Ionic equation;

2H⁺(aq) + 2Cl⁻ (aq) + 2Hg⁺(aq) + 2NO₃⁻(aq)  → Hg₂Cl₂ (s) + 2H⁺(aq) + 2NO⁻₃(aq)

Net ionic equation:

2Cl⁻ (aq) + 2Hg⁺(aq)   → Hg₂Cl₂ (s)

You might be interested in
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
Oh, so...........................................................................
uranmaximum [27]
Yes ‍♀️.................
4 0
3 years ago
The energy of a pendulum is recorded at different positions in the table below. Use the data in the table to determine the amoun
natta225 [31]

Answer:

36.55 J

Explanation:

PE = Potential energy

KE = Kinetic energy

TE = Total energy

The following data were obtained from the question:

Position >> PE >>>>> KE >>>>>> TE

1 >>>>>>>> 72.26 >> 27.74 >>>> 100

2 >>>>>>>> 63.45 >> x >>>>>>>> 100

3 >>>>>>>> 58.09 >> 41.91 >>>>> 100

The kinetic energy of the pendulum at position 2 can be obtained as follow:

From the table above, at position 2,

Potential energy (PE) = 63.45 J

Kinetic energy (KE) = unknown = x

Total energy (TE) = 100 J

TE = PE + KE

100 = 63.45 + x

Collect like terms

100 – 63.45 = x

x = 36.55 J

Thus, the kinetic energy of the pendulum at position 2 is 36.55 J.

7 0
3 years ago
What is one pro and one con of mining?
blondinia [14]

Answer:

Pro exercise con suffication

Explanation:

...

8 0
3 years ago
Both renewable and nonrenewable resources are used within our society. How do the uses of nonrenewable resources compare to the
Mila [183]

Renewable energy has the potential to have all the same applications as non-renewable. But we currently don't have the resources and potential.

So I would say the answer would be B, but this question is somewhat confusing.

4 0
3 years ago
Read 2 more answers
Other questions:
  • The water behind a dam has potential energy that can be converted to kinetic energy to turn a turbine
    12·2 answers
  • What is the mass of 37 mL but has the density of 0.79 g/mL
    11·1 answer
  • A 642 mL sample of oxygen gas at 23.5°C and 795 mm Hg, is heated to 31.7°C and the volume of the gas expands to 957 mL. What is
    10·1 answer
  • What is the final concentration if water is added to 0.50 L of a 12 M NaOH solution to make 3.0 L of a diluted NaOH solution?
    5·2 answers
  • In this molecule, what type of bond is found between the oxygen and hydrogens?
    8·1 answer
  • The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×
    10·1 answer
  • III. study the picture and level the parts of a flower. choose words inside the box<br>​
    8·1 answer
  • How you would go about separating a mixture of salt and sand. Knowing that salt will dissolve in water. Device a method to separ
    7·1 answer
  • Why do you think it is important to use the same blanace throughout the entire experiment?
    12·1 answer
  • Consider the following voltaic cell:(j) In which direction do anions within the salt bridge move to maintain charge neutrality?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!