Please, next time, please share the graph referred to in the problem statement.
You are comparing f(x)=2 ln x and g(x) = 4 ln x. The two graphs look the same, except that the amplitude (rise) in 4 ln x is exactly twice that in 2 ln x.
Thus, if 2 ln x = 3, 4 ln x = 2(3) = 6.
Answer:
∠5 = 60°
∠6 = 30°
∠7 = 120°
Step-by-step explanation:
Since the polygon is regular, you know that the central angle (7) is 1/3 of the circle, or 120°. The angle 5 is half that measure, so is 60°, and the angle 6 is the complement of angle 5, so is 30°. (Angle 6 is also half the inscribed angle at each vertex, said inscribed angle being 120°/2 = 60°.)
∠5 = 60°
∠6 = 30°
∠7 = 120°
Answer:
(k ∘ p)(x) = 2x^2 − 12x + 13
Step-by-step explanation:
k(x) = 2x^2 − 5 and p(x) = x − 3,
(k ∘ p)(x).= k(p(x))
This means put the function p(x) in for x in the function k(x)
(k ∘ p)(x) = 2(p(x)^2) -5
= 2(x-3)^2 -5
= 2 (x-3)(x-3) -5
FOIL
=2(x^2 -3x -3x+9) -5
=2 (x^2 -6x+9) -5
= 2x^2 -12x +18 -5
Combine like terms
= 2x^2 -12x +13
Answer:
BC>XY
Step-by-step explanation:
BCs angle is less than XYs angle
3(1/3x + 8) = 11
x + 24 = 11
x = 11 - 24
x = - 13