Answer:
The sum of two numbers is 14 and their difference is 10
Step-by-step explanation:
"2 numbers (x and y)
x+y = 14
and x-y + 10
If you each equation by positive 2, one gets 2x+2y = 28 and 2x-2y = 20
The 'y-terms' cancel out or equal zero when adding, so 4x = 48, divide by 4 on each side and x or the first number equals 12.
Plug 12 back into the equation for 'x' and subtract 12 on both sides so that y=2
The difference of 12-2=10 and the addition of 12 and 2 equals 14"
hopes this helps
What the question?
Or picture
From the statement of the problem, we know that:
• a train starts at City A and travels 2,158 km to City B,
,
• then it travels 3,793 km from City B to City C.
The distance between City A and City C is equal to the sum of the distance from City A to City B, and the distance from City B to City C. So the distance between City A and City C is 2,158 km + 3,793 km = 5951 km.
Looking at the answer of Clay:
<em>2,158 + 3,793 = (2,158 + 7) + (3,793 + 7) = 2,165 + 3,800 = 5,965</em>
We see that he added 7 km to each of the distances, that's the reason why he found a different a wrong result.
Answer:
a = -4
b=-29
Step-by-step explanation:
<h3>Complex number:</h3>
First write the radicals in simplest form.
i² = -1
I showed my work and answer in this picture. When simplifying square roots you can split them into a perfect squares root time the remainders
