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seraphim [82]
3 years ago
14

PLEASE HEWP :") THE STRUGGLE IS REAL MY G

Mathematics
1 answer:
andre [41]3 years ago
8 0

Answer:

i think so 3/4 If i am wrong plz anyone say the correct answer

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How many solutions does an equation have when you isolate the variable and it equals a constant
Olin [163]
There is only one solution since x=0 x cant be many things since the only thing that would make this true is 0
3 0
3 years ago
PLEASE HELP!!!!!! ILL GIVE BRAINLIEST *EXTRA 40 POINTS** !! DONT SKIP :((
elena-14-01-66 [18.8K]

Answer:

yes

Step-by-step explanation:

I think sorry if I am wrong

8 0
3 years ago
Read 2 more answers
1. A right triangle is shown below. Use the Pythagorean Theorem to determine the lengths of each side. Phythagorean Theorem: a2
erik [133]
This may not be very pretty.
(2x + 5) * (2x + 5) expanded is (use foil)
F = 4x^2
O = 2x * 5 = 10x
I = 2x + 5 = 10x
L = 25
Total = 4x^2 + 20x + 25

(x + 3)(x + 3) = x^2 + 6x + 9 by the same method

 (2x + 7)(2x + 7) = 4x^2 + 28x + 49 Same method.

4x^2 + 20x + 25 + x^2 + 6x + 9 = 4x^2 + 28x + 49
5x^2 + 26x + 34 = 4x^2 + 28x + 49 Collect everything on the left.
x^2 - 2x - 15 = 0
(x - 5)(x + 3) = 0
x + 3 will have no meaning.
x - 5 = 0
x = 5

2x + 5 = 2*5 + 5 = 15
x + 3 = 5 + 3 = 8
2x+ 7 = 2*5 +7 = 17

Check
15^2 + 8^2 = 17^2
225 + 64 = ? 289
289 = 289

a = 15 <<<<< answer
b = 8 <<<<< answer
c = 17 <<<<< answer
 


5 0
3 years ago
. 1<br> Find f<br> for the function f.<br> f(x) = 3x² + 3, x &gt; 0<br> And find the domain
konstantin123 [22]

Answer:

y = \sqrt{\frac{x-3}{3} }

Domain = [3, infinity)

Step-by-step explanation:

x = 3y^2 + 3

3y^2 = x - 3

y^2 = (x-3)/3

y = \sqrt{\frac{x-3}{3} }

8 0
3 years ago
Evaluate tan(Sin-1(-5/13)). Answer as a fraction please.
dangina [55]

Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))

Let A = arcsin(-5/13) = -arcsin(5/13)

Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0
4 years ago
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