Answer:
84
Step-by-step explanation:
Combinations
nCr
n (objects) = 9
r (sample) = 3
9C3
n! / r! (n – r)!
9! / 3! (9 – 3)!=
9! / (3! * 6!)=
9*8*7*6!/ (3! * 6!)=
6! cancels out
9*8*7/3*2*1=
3*4*7=
12*7=
84
This cannot be factored because you can'y take a number out.
This is factoring. 
This is not factoring. 
Hope this helps. :)
Given :
Length of parade , 
.
Breadth of parade , 
.
5 people can fit into a 
area.
1 mile = 5280 ft .
To Find :
The size of the crowd.
Solution :
Area of parade ,
Also , 5 people can fit in area .
So , number of people fit in A is :
Therefore , 95040 can fit in the parade .
Hence , this the required solution .
The answer is: 3.91 inches .
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Note: Volume of cylinder: V = (base area) * (height);
in which: V = volume = 384 in.³ ;
h = height = 8 in. ;
Base area = area of the base (that is; "circle") = π r² ;
in which; "r" = radius;
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Solve for "r" :
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V = π r² * (8 in.) ;
384 in.³ = (8 in.) * (π r²) ;
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Divide EACH SIDE of the equation by "8" ;
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(384 in.³) / 8 = [ (8 in.) * (π r²) in.] / 8 ;
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to get:
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48 in.³ = (π r²) in.² * in. ;
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↔ (π r²) in.² * in. = 48 in.³ ;
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Rewrite this equation; using "3.14" as an approximation for: π ;
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(3.14 * r²) in.² * in. = 48 in.³
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Divide EACH SIDE of the equation by:
"[(3.14)*(in.²)*(in.)]" ; to isolate "r² " on one side of the equation;
(since we want to solve for "r") ;
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→ [(3.14 * r²) in.² * in.] / [(3.14)*(in.²)*(in.)] = 48 in.³ / [(3.14)*(in.²)*(in.)] ;
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→ to get: r² = 48/3.14 ;
________________________
→ r² = 15.2866242038216561 ;
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To solve for "r" (the radius; take the "positive square root" of EACH side of the equation:
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→ +√(r²) = +√(15.2866242038216561)
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→ r = 3.9098112747064475286 ; round to 3.91 inches .
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