Rectangle:
A=l(w)
A=12(6)
A=72cm^2
Semicircle:
r=6/2
r=3
A=(3.14(r)^2(1/2)
A=3.14(3)^2(1/2)
A=3.14(9)(1/2)
A=14.13cm^2
A=14.1cm^2
Total area: 72cm^2 + 14.1cm^2 = 86.1cm^2
Answer:
Center: (-9, -7)
Radius: 5
Step-by-step explanation:
See the picture attached to better understand the problem
we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1
applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2
substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2
the answer isthe hypotenuse is (3√2)/2
Answer:
16.
How to find... ↓
The small triangle is 1/3 size of the big triangle.
If this is the case, find the LCF here, 4, and multiply each angle's value by the least common factor, 4.
3 x 4 (bottom) = 12
5 x 4 (right side) = 20
4 x 4 (left side <em>the missing side) </em>= 16
Therefore,
The missing side value, <em>x</em>, is 16.
Answer:
I think the answer is C.....