Which algebraic expression is equivalent to the expression below?

Mathematics

2 answers:

JulijaS [17]2 years ago

6 0

Step-by-step explanation:

7(4x + 9) - 4

= (7 × 4x) + (7 × 9) - 4

= 28x + 63 - 4

= 28x + 59

So, 7(4x + 9) - 4 is equivalent to 28x + 59 (D)

Hope it helpful and useful :)

Hunter-Best [27]2 years ago

3 0

Answer:

The answer is D

Step-by-step explanation:

Firstly, you have to get rid of brackets by expanding :

$7(4x + 9) - 4$

$= 7(4x) + 7(9) - 4$

$= 28x + 63 - 4$

Next you have to simplify :

$28x + 63 - 4$

$= 28x + 59$

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Consider the following equations. f(x) = − 4/ x3, y = 0, x = −2, x = −1. Sketch the region bounded by the graphs of the equation

Sindrei [870]

Answer:

1.5 unit^2

Step-by-step explanation:

Solution:-

- A graphing utility was used to plot the following equations:

$f ( x ) = - \frac{4}{x^3}\\\\y = 0 , x = -1 , x = -2$

- The plot is given in the document attached.

- We are to determine the area bounded by the above function f ( x ) subjected boundary equations ( y = 0 , x = -1 , x = - 2 ).

- We will utilize the double integral formulations to determine the area bounded by f ( x ) and boundary equations.

We will first perform integration in the y-direction ( dy ) which has a lower bounded of ( a = y = 0 ) and an upper bound of the function ( b = f ( x ) ) itself. Next we will proceed by integrating with respect to ( dx ) with lower limit defined by the boundary equation ( c = x = -2 ) and upper bound ( d = x = - 1 ).

The double integration formulation can be written as:

$A= \int\limits_c^d \int\limits_a^b {} \, dy.dx \\\\A = \int\limits_c^d { - \frac{4}{x^3} } . dx\\\\A = \frac{2}{x^2} |\limits_-_2^-^1\\\\A = \frac{2}{1} - \frac{2}{4} \\\\A = \frac{3}{2} unit^2$