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qaws [65]
2 years ago
10

PLSSSSS HELPPPPPPPPPPPPP

Mathematics
1 answer:
inysia [295]2 years ago
6 0

1.2 \: cubic \: feet \times  \frac{1 \: gallon}{7.48 \: cubic \: feet}  \times  \frac{8.33 \: pounds}{1 \: gallon}

= 1.33636364 pounds

I'm not too sure about tons because I don't really know what it is.

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PLEASE HELP!!!
lana [24]

EXPLANATION: By definition two lines are said to be parallel when the distance between two lines is same when measured from any point on one line.

However the criteria for intersection is that the distance between two lines should change and eventually should change to zero at intersection point.


Step-by-step explanation:

.

4 0
2 years ago
Write a real word problem that you can solve by writing an equation the answer to the problem must be 6
8_murik_8 [283]
You want to by two apples. Each apple costs three dollars. How much do you need to by two apples.
7 0
2 years ago
Plot the flowing points on the number line without measuring.​
N76 [4]

Answer:

1/4, 3/5, 8/10

Step-by-step explanation:

3/5 is greater than 1/4

(2/4 is equal to 2.5/5---that should give you a visual picture why)  

8/10 is greater than 3/5

3/5 multipled by 2 is 6/10

so, 6/10<8/10

3 0
2 years ago
Read 2 more answers
Which statement is true about judy's method?
aniked [119]
A. Judy made a mistake between Steps 1 and 2
To factor x^{2} - 16, you have to factor it as (x-2)(x+2)(x-4), not (x-2)(x+8), because that will leave an extra 6x because of 8x - 2x. 
3 0
3 years ago
Read 2 more answers
Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

4 0
3 years ago
Read 2 more answers
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