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qaws [65]
2 years ago
10

PLSSSSS HELPPPPPPPPPPPPP

Mathematics
1 answer:
inysia [295]2 years ago
6 0

1.2 \: cubic \: feet \times  \frac{1 \: gallon}{7.48 \: cubic \: feet}  \times  \frac{8.33 \: pounds}{1 \: gallon}

= 1.33636364 pounds

I'm not too sure about tons because I don't really know what it is.

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Which expression is equivalent to -3 1/8 minus 2 1/2
Sav [38]
-25/8 minus 5/2
(You just turn them into improper fractions)
8 0
3 years ago
Read 2 more answers
Easy!!!
aksik [14]

Step-by-step explanation:

f(g(10))

This is called a composite function.  It's when you plug one function into another.

First, find g(10):

g(x) = √(x-9)

g(10) = √(10-9)

g(10) = √1

g(10) = 1

Then plug that into f(x):

f(x) = -9x - 9

f(g(10)) = -9 g(10) - 9

f(g(10)) = -9 (1) - 9

f(g(10)) = -9 - 9

f(g(10)) = -18

7 0
3 years ago
High grade steel consists of 85% iron and 15% magnese. Low grade steel consists of 67% iron and 33% mag ese. NASA orders 500 ton
Mamont248 [21]

Answer:

361\dfrac{1}{9} tons of high steel and 138\dfrac{8}{9} tons of low steel

Step-by-step explanation:

Let x be the number of tons of high grade steel and y be the number of tons ow low grade steel needed.

In x tons of high grade steel there are

0.85x tons of iron

0.15x tons of magnese

In y tons of low grade steel there are

0.67y tons of iron

0.33y tons of magnese

NASA orders 500 tons of steel, so

x+y=500

and specifies that it must be in the proportion 80% iron and 20% magnese, so

0.85x+0.67y=500\cdot 0.8\\ \\0.85x+0.67y=400

From the first equation,

x=500-y

Substitute it into the second equation:

0.85(500-y)+0.67y=400\\ \\425-0.85y+0.67y=400\\ \\-0.18y=-25\\ \\y=\dfrac{2,500}{18}=138\dfrac{8}{9}\ tons\\ \\x=361\dfrac{1}{9}\ tons

7 0
3 years ago
Books at a library sale are sold for $3.50 each. A function, y = 3.50x can be used to generate an input/output table for this sc
Thepotemich [5.8K]

Answer:

the first one is the answer

Step-by-step explanation:

8 0
3 years ago
Can you please help me with 2,3,4 and 5. Will mark brainliest.
crimeas [40]
Exact
Approximation
Estimate
Exact
8 0
3 years ago
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