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hichkok12 [17]
3 years ago
7

An image formed by a mirror is virtual, upright, the same size as the object, and the same distance from the mirror as the objec

t. Which mirror produced the image? A.flat mirror B.concave mirror C.convex mirror D.spherical mirror
Physics
1 answer:
PSYCHO15rus [73]3 years ago
3 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

From the given options:

1. Flat mirror: This type of mirror is also known as plane mirror. The nature of the image formed by these mirrors is that the image is always virtual, upright, same as the size of an object and is formed at the same distance from the mirror as that of an object.

2. Concave mirror: This is a type of spherical mirror which has reflecting surface present on the inside region. The image formed by these mirrors can be virtual and upright or real and inverted. Size of the image depends on the position of the object from the mirror.

3. Convex mirror: This is a type of spherical mirror which has reflecting surface present on the outside region. The image formed by these images is always virtual, erect and of smaller size.

4. Spherical mirror: There are two types of spherical mirrors: Concave mirror and convex mirror.

Hence, the correct answer is Option A.

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Would the electron released from rest move to a region of higher electrical potential or lower electrical potential
Anni [7]

Answer:

he electron moves in the direction of a greater electric potential

Explanation:

Electric potential and electric field are related

          V = -∫ E .ds

t

he electric force is related to the electric field

           F = q E

           F = q (-dV / ds)

since the electron has charge a = 1.6 1019 C

           F = e dv / ds

therefore the electron moves in the direction of a greater electric potential

8 0
3 years ago
What would you do with the force and mass to create a situation where the car has the highest acceleration possible?
olya-2409 [2.1K]

Answer:

Increase the force and/or decrease the mass

Explanation:

A = F/m per Newton's second law, so increasing the force or decreasing the mass will increase acceleration

3 0
3 years ago
The wheel on an upside-down bicycle moves through 18.0 rad in 5.39 s. What is the wheel’s angular acceleration if its initial an
Elden [556K]

Explanation:

Formula to calculate angular acceleration is as follows.

   \Delta (\theta) = \frac{1}{2} \alpha \Delta t^{2} + \omega_{1} \Delta t

or,      \alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}

Putting the given values into the above formula as follows.

    \alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}

                = \frac{2(18.0 rad - 2.5 rad/s \times 5.30 s)}{(5.39)^{2}}    

                = 0.326 rad/s^{2}

Thus, we can conclude that the wheel’s angular acceleration if its initial angular speed is 2.5 rad/s is 0.326 rad/s^{2}.

5 0
4 years ago
Marco is conducting an experiment. He knows the wave that he is working with has a wavelength of 32.4 cm. If he measures the fre
vekshin1

This question is incomplete; here is the complete question:

Marco is conducting an experiment. He knows the wave that he is working with has a wavelength of 32.4 cm. If he measures the frequency as 3 hertz, which statement about the wave is accurate?

A. The wave has traveled 32.4 cm in 3 seconds.

B. The wave has traveled 32.4 cm in 9 seconds.

C. The wave has traveled 97.2 cm in 3 seconds.

D. The wave has traveled 97.2 cm in 1 second.

The answer to this question is D. The wave has traveled 97.2 cm in 1 second.

Explanation:

The frequency of a wave, which is in this case 3 hertz, represents the number of waves that go through a point during 1 second. According to this, if the frequency of the wave is 3 hertz this means in 1 second there were 3 waves. Moreover, if you multiply the wavelength (32.4cm) by the frequency (3) you will know the distance the wave traveled in 1 second: 32.4 x 3 =  97.2 cm. This makes option D the correct one as the distance in 1 second was 97.2 cm.

8 0
3 years ago
Which of the following would not be found on the electromagnetic spectrum?
kondor19780726 [428]
All wavelengths and frequencies of electromagnetic radiation ...
including visible light ... are features of the electromagnetic spectrum.

Sound waves have nothing to do with the electromagnetic spectrum.
8 0
3 years ago
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