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AURORKA [14]
3 years ago
6

Would the electron released from rest move to a region of higher electrical potential or lower electrical potential

Physics
1 answer:
Anni [7]3 years ago
8 0

Answer:

he electron moves in the direction of a greater electric potential

Explanation:

Electric potential and electric field are related

          V = -∫ E .ds

t

he electric force is related to the electric field

           F = q E

           F = q (-dV / ds)

since the electron has charge a = 1.6 1019 C

           F = e dv / ds

therefore the electron moves in the direction of a greater electric potential

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Which of the following devices could be used to create a position--time graph for an object? 
pickupchik [31]
D none of the above

all of them is related to energy and motion , not to positioning.
6 0
4 years ago
Which is the best description for the lines I and k
hodyreva [135]
"Unknown, unspecified, unillustrated, undepicted, undescribed, undemonstrated, undefined, potentially non-existent."
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3 years ago
A 110 kg football player running with a velocity of 5.0 m/s hits another stationary football
KengaRu [80]

Answer:

The final velocity of the second player is 6.1 m/s.

Explanation:

The final velocity of the second player can be calculated by conservation of linear momentum (p):

p_{i} = p_{f}  

m_{a}v_{a_{i}} + m_{b}v_{b_{i}} = m_{a}v_{a_{f}} + m_{b}v_{b_{f}}  (1)

Where:

m_{a}: is the mass of the first football player = 110 kg

m_{b}: is the mass of the second football player = 90 kg

v_{a_{i}}: is the initial velocity of the first football player = 5.0 m/s

v_{b_{i}}: is the initial velocity of the second football player = 0 (he is at rest)

v_{a_{f}}: is the final velocity of the first football player = 0 (he stops after the impact)

v_{b_{f}}: is the final velocity of the second football player =?

By solving equation (1) for v_{b_{f}} we have:

110 kg*5.0 m/s + 0 = 0 + 90 kg*v_{b_{f}}

v_{b_{f}} = \frac{110 kg*5.0 m/s}{90 kg} = 6.1 m/s

Therefore, the final velocity of the second player is 6.1 m/s.

I hope it helps you!

8 0
3 years ago
Parallel rays from a distant object are traveling in air and then are incident on the concave end of a glass rod with a radius o
skad [1K]

Answer:

the distance of image from the vertex is 45 cm and the image formed is in the glass.

Explanation:

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radius of curvature, R = - 15 cm

refractive index, n = 1.5

Let the distance of image is v.

Use the formula

-\frac{n1}{u}+\frac{n2}{v}=\frac{n2- n1}{R}\\\\-\frac{1}{\infty }+\frac{1.5}{v}=\frac{1.5-1}{-15}\\\\v=45   cm

The image is in the glass.  

8 0
3 years ago
How do solar panels create electricity
xenn [34]

Answer:

They create electricity from the sun's  rays

Explanation:

By the use of "solar cells" or "solar panel", you can trap solar energy in silicon/germanium rods, then you can convert in into electricity too. Solar powered panels convert the sun's rays into electricity by exciting electrons in silicon cells using the photons of light from the sun. This electricity can then be used to supply renewable energy to your home or business.

5 0
3 years ago
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