Calculate the magnitude of the force the jumper must exert on the ground to produce an upward acceleration 4.00 times the accele
2 answers:
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Answer:
K = 588.3 N/m
Explanation:
From a forces diagram, and knowing that for the maximum value of K, the crate will try to rebound back up (Friction force will point downward):
Fe - Ff - W*sin(22) = 0 Replacing Fe = K*X and then solving for X:
By conservation of energy:
Replacing our previous value for X and solving the equation for K, we get maximum value to prevent the crate from rebound:
K = 588.3 N/m
Answer:
θ = 30°
Explanation:
Firts, the angle when the beam of light passes through the block cam be calculated using Snell Law:
<u>Where</u>:
n₁: is the index of refraction of the incident medium (air) = 1
θ₁: is the incident angle = 30°
n₂: is the medium 2 (plastic) = 1.46
θ₂: is the transmission angle
Hence, θ₂ is:
Now, when the beam of light re-emerges from the opposite side, we have:
n₁: is the index of refraction of the incident medium (plastic) = 1.46
θ₁: is the incident angle = 20.03°
n₂: is the medium 2 (air) = 1
θ₂: is the transmission angle
Hence, the angle to the normal to that surface (θ₂) is:
Therefore, we have that the beam of light will come out at the same angle of when it went in, since, it goes from air and enters to a plastic medium and then enters again in this medium to go out to air again. This was proved using the Snell Law.
I hope it helps you!