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3 years ago

Find the volume of the following figure. Round your answer to the nearest whole

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

8 0

Answer:

210cm

Step-by-step explanation:

B=l•w

B=5•6

B=30

V=B•h

V=30•7

V=210

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(2x -18x) +(14y) +(9 -10) = -16x +14y -1

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2x -18x +14y -19 = -16x +14y -19 . . . not the same
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4 years ago

Read 2 more answers

What are the solutions of x^2-2x+5=0

sweet [91]

The solution of $x^{2}-2 x+5=0$ are 1 + 2i and 1 – 2i

Solution:

Given, equation is $x^{2}-2 x+5=0$

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ --- (1)

Let us determine the nature of roots:

Here in $x^{2}-2 x+5=0$ a = 1 ; b = -2 ; c = 5

$b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16$

Since $b^2 - 4ac < 0$ , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

$x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}$

On solving we get,

$x=\frac{2 \pm \sqrt{4-20}}{2}$

$x=\frac{2 \pm \sqrt{-16}}{2}$

$x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}$

we know that square root of -1 is "i" which is a complex number

$\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}$

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

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Answer:

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Step-by-step explanation:

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3 years ago

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Anuta_ua [19.1K]

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3 years ago

Line RS bisects PQ at point R, Find RQ if PQ = 14 cm

Dovator [93]

If PQ is 14, each segment, PR and RQ will be 7.
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3 years ago