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3 years ago

Divide. Express the quotient in simplest form. 3 ÷ 1/4 = m

Mathematics

2 answers:

makkiz [27]3 years ago

4 0

Answer:

M= 12

Step-by-step explanation:

solve for M by simplifying the answer both sides of the equation.

Serhud [2]3 years ago

3 0

Answer:

M = 12

Step-by-step explanation:

3 / 1/4 = 12

3/.25 = 12

.25 x 12 = 3

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Leona purchased a $1,000 bond having a quoted price of 99.875. She had to pay a 5.5% brokerage fee (of the selling price). What

iogann1982 [59]

Answer:

None of these choices are correct.

Step-by-step explanation:

If a bond is quoted at 99.875, it means that it is sold at 99.875% of the face value;

Face value = 1000

Therefore, Price = 0.99875 * 1000

Price = $998.75

If Leona pays 5.5% of the selling price, it means that she is paying additional cost which will make the total cost more than the quoted price;

5.5% of 998.75 is;

0.055*998.75 = $54.93

The total cost = $998.75 +$54.93

= $1053.68

Therefore, none of the given choices is correct.

4 0

3 years ago

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The amount of money the athletic booster club raised for the year is modeled by the function f(x) = 250x + 750. How much money d

nataly862011 [7]

The answer is b) $750

7 0

3 years ago

Read 2 more answers

Solve the system using substitution.

valkas [14]

Good evening ,

Answer:

Step-by-step explanation:

y=5x then

4x-y= -3 ⇌ 4x-5x= -3 ⇌ -x= -3 ⇌ x=3

and since y=5x then y=5×3=15.

______________________________

5 0

3 years ago

Given LaTeX: f\left(x\right)=x^{^3}-3x+4f ( x ) = x 3 − 3 x + 4, determine the intervals where the function is increasing and wh

Vedmedyk [2.9K]

Answer:

Increasing: $x$ and $x>1$ .

Decreasing: $-1$

Step-by-step explanation:

We have been given a function $f(x)=x^3-3x+4$ . We are asked to determine the intervals, where the function is increasing and where it is decreasing.

First of all, we will find critical points of our given function by equating derivative of our given function to 0.

Let us find derivative of our given function.

$f'(x)=\frac{d}{dx}(x^3)-\frac{d}{dx}(3x)+\frac{d}{dx}(4)$

$f'(x)=3x^{3-1}-3+0$

$f'(x)=3x^{2}-3$

Let us equate derivative with 0 as find critical points as:

$0=3x^{2}-3$

$3x^{2}=3$

Divide both sides by 3:

$x^{2}=1$

Now we will take square-root of both sides as:

$\sqrt{x^{2}}=\pm\sqrt{1}$

$x=\pm 1$

$x=-1,1$

We know that these critical points will divide number line into three intervals. One from negative infinity to -1, 2nd -1 to 1 and 3rd 1 to positive infinity.

Now we will check one number from each interval. If derivative of the point is greater than 0, then function is increasing, if derivative of the point is less than 0, then function is decreasing.

We will check -2 from our 1st interval.

$f'(-2)=3(-2)^{2}-3=3(4)-3=12-3=9$