Answer:
1. The network address for 172.22.49.252/17 is 172.22.0.0/17.
2. The last valid assignable host address of 172.22.4.129/26 is 172.22.4.190.
3. The first and last host address of 192.167.25.25/16 is 192.167.0.1 and 192.167.255.254.
4. The broadcast address of 10.75.96.0/20 is 10.75.111.255
Explanation:
Subnetting in networking is the process of managing the use of host addresses and subnet masks of a network IP address. For example, the IP address "172.22.49.252/17" is a class B address that receives an extra bit from the third octet which changes its subnet-mask from "255.255.0.0" to "255.255.128.0". with this, only 32766 IP addresses are used, with the network address of "172.22.0.0/17".
Answer:
chemați. mfvd5. fn. cfcfcfcfcfcfcf 4t
It would either be A. Audio card or D. Sound card but most likely A
Options :
A.) s1 < s2
B.) s1 <= s2
C.) s1.compareTo(s2) == −1
D.) s2.compareTo(s1) < 0
E.) s1.compareTo(s2) < 0
Answer: E.) s1.compareTo(s2) < 0
Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.
If first string = s1 ; second string = s2
To compare s1 with s2, the format is ;
s1.compareTo(s2) ;
If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.
If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.
If both are s1 and s2 are the same, the output will be 0.
