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yuradex [85]
3 years ago
15

Please help!!!!!11!!!111!!!!!!!!

Mathematics
1 answer:
morpeh [17]3 years ago
4 0

Answer:

40

Step-by-step explanation:

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What is the final amount if 1235 is increased by 4% followed by a 4% decrease?
madam [21]

Answer:

1233.02 to 2 D.P.

Step-by-step explanation:

4 % = 0.04

So to obtain the amount after increase by 4% we multiply by 1.04:

1235 * 1.04 = 1284.4

Decreasing by 4%:  we mutriply by 1 - 0.04 = 0.96:

1284.4 * 0.96

= 1233.024.

4 0
3 years ago
Read 2 more answers
What is 11.5 times 30
Lelechka [254]

Answer:

345

Step-by-step explanation:

6 0
2 years ago
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The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
2 years ago
In 3 apples cost 48¢ , how many dozen apples can be bougth for $3.84?
inn [45]
Ok so let’s do .48/3 then divide 3.84 by our answer to get 24
7 0
2 years ago
Read 2 more answers
If Robbie has twenty-five apples and he wants to share them equally with four other friends, how many apples must he give to eac
patriot [66]

Answer:

5 apples

Step-by-step explanation:

4 friends + Robby = 5 people

25 apples in total ÷ 5 people

= 5 apples per person

7 0
1 year ago
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