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2 years ago

[21] Please help. What is the volume of the cooler in cubic inches?

Mathematics

1 answer:

GenaCL600 [577]2 years ago

6 0

Answer:

3,724

Step-by-step explanation: Length x width x height

19 x 14 x 14

19 x 14 = 266

266 x 14 = 3,742

hope this helped :)

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Find the length of EF

Lisa [10]

Answer:

Step-by-step explanation:

1. First, we need to set up an equation to find the value of x and then the length of EF.

2. We know that DG is equal to 33, so we can add all the three sections it's cut into altogether to get 33. Therefore, we get an equation of: $3x - 28 + 3x - 30 + x = 33$

3. (Solving for x)

Step 1: Simplify both sides of the equation.

$3x - 28 + 3x - 30 + x = 33$
$(3x+3x+x) + (-28-30)=33$
$7x - 58 = 33$

Step 2: Add 58 to both sides.

$7x - 58 + 58 = 33 + 58$
$7x = 91$

Step 3: Divide both sides by 7.

$\frac{7x}{7} = \frac{91}{7}$
$x = 13$

4. Now that we know x is equal to 13, we can plug that value in for the expression 3x - 30.

$3(13)-30$
$39 - 30$
$9$

Therefore, the length of EF is 9.

7 0

3 years ago

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11111nata11111 [884]

Answer:

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Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Any flvs algebra students wanna help me out? :')

kirza4 [7]

34.5 is correct because

7 0

3 years ago

Two sides of a triangle have lengths 10 and 18. Which inequalities describe the possible lengths for the third side x?

puteri [66]

Let with X is denoted the length of the third side.
For a triangle the following statements must be true:
The sum of the lengths of any two sides of a triangle is greater than the length of the third side.
This means that this inequality can be written: X<10+18 ,X<28

7 0

3 years ago

The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and

NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

$60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120$

Let's find h with the quadratic formula:

$\fbox {Quadratic formula:} \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}$

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation

$\fbox {Pythagorean equation:}$ The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle).