Answer: 
Explanation:
Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.
The given chemical equation is:
The complete ionic equation is;
The ions which are present on both the sides of the equation are 
and 
and are not involved in net ionic equation.
Hence, the net ionic equation is :
I think so because I did this before
Answer:
1.45 *10^23 atoms C
Explanation:
3.50 g butane * 1 mol butane/58.1 g butane =0.06024 mol butane
in 1 mol C4H10 -------- 4 mol C
in 0.06024 mol C4H10 -------- 4*0.6024 = 0.241 mol C
0.241 mol C * 6.02*10^23 atoms C/1 mol C = 1.45 *10^23 atoms C
1) Chemical reaction (thermal decomposition)
2NaHCO3 (s) ---> Na2CO3 (s) + H2O (g) + CO2(g)
2) Reasoning
The lost of mass is due to the lost of the gases H2O and CO2.
So, you can calculate the mass of Na2CO3 obtained from 1.000 g NaHCO3, and the difference will be the mass lost.
2) Convert 1.000 g of NaHCO3 to number of moles
molar mass NaHCO3: 1*23g/mol + 1*1g/mol + 1*12g/mol + 3*16g/mol = 84 g/mol
number of moles = mass in grams / molar mass = 1.000 g / 84 g/mol = 0.01190 moles
3) Use therotecial molar ratios:
2 moles NaHCO3 : 1 mol Na2CO3
=> 0.01190 mol NaHCO3 / x = 2 mol NaHCO3 / 1mol Na2CO3
=> x = 1mol Na2CO3 * 0.01190 mol NaHCO3 / 2 mol NaHCO3
=> x = 0.00595 mol Na2CO3
4) Convert 0.0595 mol Na2CO3 to mass
molar mass Na2CO3: 2*23g/mol + 1*12g/mol + 3*16g/mol = 106 g/mol
mass in grams = number of moles * molar mass = 0.00595 mol * 106 g/mol = 0.6307 g
5) lost mass
1.000g - 0.6307g = 0.3693 g
Answer: 0.3693 g
