All categories

2 years ago

the quantity PV/T must be held constant and both P and V are doubled, the value of T will necessarily have to,

1 answer:

7 0

Quadruple
Since we double both P and V in the numerator, the denominator (T) has to be doubled twice, or quadrupled (multiplied by 4)

Example:

P1 = 5
V1 = 2
T1 = 10
5*2/10 = 1

P2 = 5*2 = 10
V2 = 2*2 = 4
T2 = 10*4 = 40
10*4/40 = 40

You might be interested in

Write the chemical symbol for an element in Period 6 and Group 2A

Nataly_w [17]

The answer is Ba (56)

3 0

4 years ago

What do most decomposition reactions require

NikAS [45]

Answer: Most decomposition reactions require an input of energy in the form of heat, light, or electricity. Binary compounds are compounds composed of just two elements. The simplest kind of decomposition reaction is when a binary compound decomposes into its elements.

7 0

4 years ago

Read 2 more answers

Outline the steps needed to determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.

kumpel [21]

Answer : The limiting reactant is $O_2$

Explanation : Given,

Mass of $C_3H_8$ = 30.0 g

Mass of $O_2$ = 75.0 g

Molar mass of $C_3H_8$ = 44 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $C_3H_8$ and $O_2$ .

$\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{30.0g}{44g/mole}=0.682moles$

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{75.0g}{32g/mole}=2.34moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

From the balanced reaction we conclude that

As, 5 mole of $O_2$ react with 1 mole of $C_3H_8$

So, 2.34 moles of $O_2$ react with $\frac{2.34}{5}\times 1=0.468$ moles of $C_3H_8$

From this we conclude that, $C_3H_8$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

Therefore, the limiting reactant is $O_2$

5 0

3 years ago

How many grams are in 4.5 x 10^22 molecules of water? please show dimensional analysis

GaryK [48]

Answer:

1.1grams

Explanation:

Find moles of water:

4.5x10^22/(6.02x10^23)=0.07mol

Find molar mass of the water

O=16.00g/mol

0.07x 16.00=1.1 grams

4 0

3 years ago

Which describes the role of carbon dioxide in photosynthesis?

jeka57 [31]

Answer:

It is a reactant, so it enters the plant.

Explanation:

Hello,

Photosynthesis is the natural process occurring when plants produce sugar and oxygen by using the visible light as the catalyst to undergo the following chemical reaction:

$6CO_2+6H_2O-->C_6H_{12}O_6+6O_2$

In such a way, it is seen that the carbon dioxide has the role of reactant as it is used by the plant, that is, it enters the plant to allow the photosynthesis to be carried out.

Best regards.

6 0

3 years ago

Read 2 more answers