Please help me with this one. I think it’s right but can someone double check it.

What could cause a less than 100% yield?

Phantasy [73]

That’s a dumb question, because It depends on the experiment. I would guess “a” or “d” because in most cases running out of time during a lab, or getting impatient, etc can give you a lower yield.

Unless I’m misreading “d”, it just seems like a more in-depth version of “a”. So it wouldn’t hurt to try that one.

8 0

4 years ago

In which organ in <br> a earthworm can I find the content to be most ground up and why

Yanka [14]

The intestines

By the time food has reached the intestines, it has already passed through the gizzard (where it is ground up) and has nutritious pieces absorbed before waste is passed to the excretory system.

8 0

3 years ago

What happens when you put metal into hot galium?

Mice21 [21]

Answer:

Aluminum Gallium Reaction- Gallium reacts with Aluminum to create an Aluminum alloy that crumbles at the touch. Gallium attacks many metals including Aluminum & Steel by diffusing into the grain boundaries making them extremely brittle. Gallium easily alloys with many metals in low quantities

Explanation:

3 0

3 years ago

A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a

Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$q=mc\Delta T$

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

$q_{released}=q_{absorbed}\\
q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T$

The given mass of calorimeter has been, $m_{calorimeter}=1350\;\rm g$

The specific heat of the calorimeter has been, $c_{calorimeter}=5.82\;\rm J/g^\circ C$

The change in temperature of the calorimeter has been, $\Delta T=2.87^\circ \rm C$

Substituting the values for heat released:

$q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\
q_{released}=22,549.5\;\text J\\
q_{released}}=22.54\;\rm kJ$

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0

3 years ago

ANSWER ASAP PLEASE!<br> Balance the following equation:<br> _Fe + _O₂ --> _FeO₃

ira [324]

It would be. 2Fe + 3O2 ——> 2Fe03. You have to make oxygen 6 on both sides in order to balance, then you can do Fe. Which on the right would be 2 by making oxygen 6. Then add the 2 to the other side to balance it.

8 0

3 years ago