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3 years ago

What is the scale factor of ABC to ADEF?

Mathematics

1 answer:

kolbaska11 [484]3 years ago

8 0

Sorry, I haven't learned this yet ;-;

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What is 20 increased by 50%

slamgirl [31]

Answer:

30.00

Step-by-step explanation:

20 Increased By 50% Is 30.00

4 0

2 years ago

Read 2 more answers

Valentin [98]

Answer:

30:1

Step-by-step explanation:

90:3

90÷3=30

3÷3=1

=30:1

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3 years ago

Compute each quotient using the identities you discovered in this lesson.x^4-16/x-2

luda_lava [24]

Answer:

The quotient will be $(x^2+4)(x+2)$

Step-by-step explanation:

We have given the equation $\frac{x^4-16}{x-2}$

We have to find the quotient

From algebraic equation we know that $a^2-b^2=(a+b)(a-b)$

So $\frac{x^4-16}{x-2}=\frac{(x^2)^2-4^2}{x-2}=\frac{(x^2+4)(x^2-4)}{x-2}=\frac{(x^2+4)(x+2)(x-2)}{x-2}=(x^2+4)(x+2)$

So the quotient will be $(x^2+4)(x+2)$

8 0

2 years ago

The average density of the material in intergalactic space is approximately 2.5 × 10–27 kg/m3. what is the volume of a lead samp

Lesechka [4]

Answer:

e. $1.8\times 10^{-6}m^3$

Step-by-step explanation:

It is given that,

The density of intergalactic space material is $2.5 \times 10^{-27}$ kg per cubic meter.

And the volume of intergalactic space material is $8.0\times 10^{24} m^3$

So the mass of that much intergalactic space material is,

$m= \rho\times v$ , where 'm' is the mass, and 'v' is the volume.

Putting the values we get,

$m=2.5 \times 10^{-27}\times 8.0 \times 10^{24}$

$m=20\times 10^{(-27+24)}=20\times 10^{-3} kg$

It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is $20 \times 10^{-3}=2 \times 10^{-2}kg$

So the volume of lead is,

$v=\frac{m}{\rho} =\frac{2 \times 10^{-2}}{11300} = 0.00000177 m^3$

$v=1.77 \times 10^{-6}=1.8\times 10^{-6}m^3$

So the volume of lead is $v=1.8\times 10^{-6}m^3$ .

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3 years ago

Trapezoid WKLX has vertices W(2, −3), K(4, −3), L(5, −2) , and X(1, −2) . Trapezoid WKLX is translated 4 units right and 3 uni

s344n2d4d5 [400]

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3 years ago