Answer: I kin tommyinnit
Red foxes is the top one
White spruces and willows are the producers
the bottom one is Lynx and hawk.
E = h * f
<span>so f = E / h = (1.99 *10^-19)/*(6.63*10^-34) </span>
<span>=3.00*10^14 Hz </span>
Answer:
i only found the 49, hope it still helps, mate
49. In this question (t½) of C-14 is 5730 years, which means that after 5730 years half of the sample would have decayed and half would be left as it is.
After 5730 years ( first half life) 70 /2 = 35 mg decays and 35 g remains left.
After another 5730 years ( two half lives or 11460 years) 35 /2 = 17.5mg decays and 17.5 g remains left .
After another 5730 years ( three half lives or 17190 years) 17.5 /2 = 8.75mg decays and 8.75g remains left.
after three half lives or 17190 years, 8.75 g of C-14 will be left.
Answer:
Follows are the solution to this question:
Explanation:
Given value:
In point a:
Calculating the process of Isothermal, when the temperature is constant:
In point b:
Calculating the adiobatic process:
In point c:
workdone by gas is 1.018 KJ
What's your question BTW?
Can't understand what u have typed