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Valentin [98]
3 years ago
9

Which type of orbitals overlap to form the sigma bond between C and N in H−C≡N:? Which type of orbitals overlap to form the sigm

a bond between and in ?
Chemistry
1 answer:
zysi [14]3 years ago
8 0

Explanation:

When carbon atom tends to form single bonds then its hybridization is sp^{3}, when carbon atom tends to form double bond then its hybridization is sp^{2} and when a carbon atom is attached to a triple bond or with two double bonds then its hydridization is sp.

For example, in HCN molecule there is a triple existing between the carbon and nitrogen atom.

So, hybridization of carbon in this molecules is sp. Moreover, nitrogen atom is also attached via triple bond and it also has a lone pair of electrons. Hence, the hybridization of nitrogen atom is also sp.

Thus, we can conclude that s and p type of orbitals overlap to form the sigma bond between C and N in H−C≡N:

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Which of the following solutions would have the most basic pH? Assume that they are all 0.10 M in acid at 25C. The acid is follo
pychu [463]

Answer:

Explanation:

Given:

Ka of HClO2 = 1.1 × 10-2

Ka of HCHO2 = 1.8 × 10-4

Ka of HCN = 4.9 × 10-10

Ka of HNO2 = 4.6 × 10-4

Ka of HF = 3.5 × 10-4

All at a concentration of 0.1 M

A.

HA --> H+ + A-

Ka = [H+] × [A-]/[HA]

[H+] = [A-] = x

[HClO2] = 0.1 M

HClO2 --> ClO2^- + H+

1.1 × 10-2 = x^2/0.1

x = sqrt(1.1 × 10^-3

= 0.033 M

pH = -log[H+]

= 1.48

B.

HA --> H+ + A-

Ka = [H+] × [A-]/[HA]

[H+] = [A-] = x

[HCHO2] = 0.1 M

HCHO2 --> CHO2^- + H+

1.8 × 10-4 = x^2/0.1

x = sqrt(1.8 × 10^-5)

= 0.0042 M

pH = -log[H+]

= 2.37

C.

HA --> H+ + A-

Ka = [H+] × [A-]/[HA]

[H+] = [A-] = x

[HCN] = 0.1 M

HCN --> CN- + H+

4.9 × 10-10 = x^2/0.1

x = sqrt(4.9 × 10-11)

= 0.000007 M

pH = -log[H+]

= 5.16

D.

HA --> H+ + A-

Ka = [H+] × [A-]/[HA]

[H+] = [A-] = x

[HNO2] = 0.1 M

HNO2 --> NO2^- + H+

4.6 × 10-4 = x^2/0.1

x = sqrt(4.6 × 10-5)

= 0.0068 M

pH = -log[H+]

= 2.17

E.

HA --> H+ + A-

Ka = [H+] × [A-]/[HA]

[H+] = [A-] = x

[HF] = 0.1 M

HF --> F- + H+

3.5 × 10-4 = x^2/0.1

x = sqrt(3.5 × 10-5)

= 0.0059 M

pH = -log[H+]

= 2.23

a) pH = 1.48

b) pH = 2.37

c) pH = 5.16

d) pH = 2.17

e) pH = 2.33

HCN is most basic because;

smallest Ka

Highest pH value = 5.16

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