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3 years ago

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Which type of orbitals overlap to form the sigma bond between C and N in H−C≡N:? Which type of orbitals overlap to form the sigm

a bond between and in ?

1 answer:

zysi [14]3 years ago

8 0

Explanation:

When carbon atom tends to form single bonds then its hybridization is $sp^{3}$ , when carbon atom tends to form double bond then its hybridization is $sp^{2}$ and when a carbon atom is attached to a triple bond or with two double bonds then its hydridization is sp.

For example, in HCN molecule there is a triple existing between the carbon and nitrogen atom.

So, hybridization of carbon in this molecules is sp. Moreover, nitrogen atom is also attached via triple bond and it also has a lone pair of electrons. Hence, the hybridization of nitrogen atom is also sp.

Thus, we can conclude that s and p type of orbitals overlap to form the sigma bond between C and N in H−C≡N:

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Explanation:

When we balance a chemical equation, what we are trying to do is to achieve the same number of atoms for each element on both sides of the arrow. On the right of the arrow is where we can find the products, while the reactants are found on the left of the arrow.

We usually balance O and H atoms last.

AsCl₃ + H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 1

Cl --- 3

H --- 2

S --- 1

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

2 AsCl₃ + H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 2

S --- 1

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of As atoms is now balanced.

2 AsCl₃ + 3 H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of S atoms is now equal on both sides.

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

<u>products</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

The equation is now balanced.

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2 years ago