Need help fast this is time
1 answer:
You might be interested in
Answer:
A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].
Step-by-step explanation:
We are given the weights, in the ounces, of a sample of 12 boxes below;
Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. = ~
where, = sample mean weight =
= 21.88 ounces
s = sample standard deviation = = 0.201 ounces
n = sample of boxes = 12
= population mean weight
<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>
<u>So, 90% confidence interval for the population mean, </u><u> is ;</u>
P(-1.796 < < 1.796) = 0.90 {As the critical value of t at 11 degrees of
freedom are -1.796 & 1.796 with P = 5%}
P(-1.796 < < 1.796) = 0.90
P( <
<
) = 0.90
P( <
<
) = 0.90
<u>90% confidence interval for</u> = [
,
]
= [ ,
]
= [21.78, 21.98]
Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].