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Viefleur [7K]
3 years ago
11

Item 5 A spotlight on the ground shines a beam of light to the top of a tree that is 12 m tall. The beam of light makes an angle

of 40° with the ground. What is the distance from the spotlight to the base of the tree, rounded to the nearest meter? 10 m 14 m 16 m 19 m PreviousFinish

Mathematics
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

14 m

Step-by-step explanation:

We are given that

Height of tree=AB=12 m

\theta=40^{\circ}

We have to find the distance from the spotlight to the base of the tree.

We know that

tan\theta=\frac{perpendicular\;side}{base}

\frac{AB}{BC}=tan40

\frac{12}{BC}=tan40

BC=\frac{12}{tan40}=14.3\approx 14

Hence, the distance from the spotlight to the base of the tree=14 m

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<span>Equation at the end of step  2  :</span>  6x2 - x - 4 = 0 <span>((2•3x2) - x) - 4 = 0 </span><span>Step  2  :</span>Trying to factor by splitting the middle term

<span> 2.1 </span>    Factoring <span> 6x2-x-4</span> 

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The last term, "the constant", is <span> -4 </span>

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Observation : No two such factors can be found !! 
Conclusion : Trinomial can not be factored

<span>Equation at the end of step  2  :</span><span> 6x2 - x - 4 = 0 </span>

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