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Viefleur [7K]
3 years ago
11

Item 5 A spotlight on the ground shines a beam of light to the top of a tree that is 12 m tall. The beam of light makes an angle

of 40° with the ground. What is the distance from the spotlight to the base of the tree, rounded to the nearest meter? 10 m 14 m 16 m 19 m PreviousFinish

Mathematics
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

14 m

Step-by-step explanation:

We are given that

Height of tree=AB=12 m

\theta=40^{\circ}

We have to find the distance from the spotlight to the base of the tree.

We know that

tan\theta=\frac{perpendicular\;side}{base}

\frac{AB}{BC}=tan40

\frac{12}{BC}=tan40

BC=\frac{12}{tan40}=14.3\approx 14

Hence, the distance from the spotlight to the base of the tree=14 m

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Can someone help and give me a step by step explanation please?!
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9514 1404 393

Answer:

  • ∠QSR = 78°
  • ∠SQR = 51°

Step-by-step explanation:

The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...

  ∠QSR = 2×∠QTR

  ∠QSR = 2×39°

  ∠QSR = 78°

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Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...

  ∠QSR + 2(∠SQR) = 180°

  78° + 2(∠SQR) = 180° . . . . fill in the value we know

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  ∠SQR = 51° . . . . . . . . . . . . .divide by 2

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3 years ago
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Answer:

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Step-by-step explanation:

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