In circular motion, the centripetal force is v²/R , and the
centripetal force is (mass) x (acceleration) = M v²/R .
1400 = 2100 v² / 150
Divide each side by 2100 : 2/3 = v² / 150
Multiply each side by 150 : 100 = v²
Square root each side: v = 10 m/s .
Answer:
The correct answer is d d= 30 m
Explanation:
The electric force is given by
Fe = q E
Since the particle charge is negative, the force and acceleration oppose the movement, let's use Newton's second law
F = m a
q E = m a
a = q E / m
Let's reduce
q = -5.0 mC = -5.0 10⁻⁶ C
m = 20 mg = 20 10⁻³ g (1kg / 1000 g) = 20 10⁻⁶ kg
a = - 5.0 10⁻⁶ 60/20 10⁻⁶
a = -15 m / s²
Now we can use kinematics
v² = v₀² + 2 a d
At the point where stop (v=0)
0 = v₀² + 2 a d
d = - v₀² / 2 a
d = 30² / (2 -(15))
d = 30 m
The correct answer is d
Answer:
0 J
Explanation:
Gravitational potential energy is:
PE = mgh
where m is mass, g is acceleration due to gravity, and h is the height.
Right before the coin hits the ground, its height above the ground is 0 m, so the potential energy is:
PE = mgh
PE = (0.005 kg) (9.8 m/s²) (0 m)
PE = 0 J
Answer:
V = 6.65 [volt]
Explanation:
First, we must calculate the power by means of the following equation, where the voltage is related to the energy produced or consumed in a given time.
Using the power we can calculate the voltage, by means of the following equation that relates the voltage to the current.
where:
V = voltage [Volts]
I = current = 200 [mA] = 0.2 [A]