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Ratling [72]
3 years ago
12

during convection, hot material _____ (expands & sinks, cools & rises, expands & rises, deflates & rises) then m

oves to the side and _____. ( cools & sinks, deflates & rises, expands & sinks, warm & rises) this circular pattern is called a convection current.
Physics
2 answers:
Lady bird [3.3K]3 years ago
4 0

Answer:

During convection, hot material expands & rises then moves to the side and cools & sinks. this circular pattern is called a convection current.

Explanation:

Convection is one of the three methods of transfer of heat. It occurs only in fluids (liquids or gases).

Convection occurs when there is a source of heat that heats a fluid, such as in a boiling pot of water. The water which is on the bottom of the pot becomes warmer before than the water at the top (because it is closer to the flame), and so it becomes less dense: for this reason, it expands and it becomes rising. On the contrary, the water on top is colder, so it is more dense and starts sinking, replacing the warmer water. As the new part of water gets warmer, it starts rising, and so the process is continuously repeated. This circular current is called convection current.

Tju [1.3M]3 years ago
4 0
During convection, hot material expands and rises then moves to the side and cools and sinks.
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A Ferris wheel with 60 spokes has a diameter of 100 m. It makes one rotation every 60 seconds. Find the speed of the passengers
Doss [256]

Answer:

<em>The speed of the passengers is 5.24 m/s</em>

Explanation:

<u>Uniform Circular Motion </u>

It occurs when an object in a circular path travels equal angles in equal times.

The angular speed can be calculated in two different ways:

\displaystyle \omega=\frac{v}{r}

Where:

v = tangential speed

r = radius of the circle described by the rotating object

Also:

\omega=2\pi f

Where:

f = frequency

Since the frequency is calculated when the number of revolutions n and the time t are known:

\displaystyle f=\frac{n}{t}

The Ferris wheel has a diameter of 100 m and makes n=1 rotation in t=60 seconds, thus the frequency is:

\displaystyle f=\frac{1}{60}\ Hz

The angular speed is:

\displaystyle \omega=2\pi \frac{1}{60} =\frac{\pi}{30} \ rad/s

Now we calculate the tangential speed, solving this formula for v:

\displaystyle \omega=\frac{v}{r}

v=\omega . r

The radius is half the diameter, r=100/2=50 m:

\displaystyle v=\frac{\pi}{30} . 50

Calculating:

v = 5.24 m/s

The speed of the passengers is 5.24 m/s

7 0
2 years ago
4. A group of students made a rocket and launched it vertically upwards with velocity
Aleks04 [339]

Answer:

Approximately 72.9\; \rm m, assuming that the rocket had no propulsion onboard, and that air resistance on the rocket is negligible.

Explanation:

Initial velocity of this rocket: u = 27\; \rm m\cdot s^{-1}.

When the rocket is at its maximum height, the velocity of the rocket would be equal to 0. That is: v = 0\; \rm m \cdot s^{-1}.  

The acceleration of the rocket (because of gravity) is constantly downwards, with a value of a = -g = -10\; \rm m \cdot s^{-2}.

Let x denote the distance that the rocket travelled from the launch site to the place where it attained maximum height. The following equation would relate x \! to u, v, and a:

\displaystyle x = \frac{v^2 - u^2}{2\, a}.

Apply this equation to find the value of x:

\begin{aligned} x &= \frac{v^2 - u^2}{2\, a} \\ &= \frac{\left(0\; \rm m\cdot s^{-1}\right)^{2} - \left(27\; \rm m \cdot s^{-1}\right)^{2}}{2 \times 10\; \rm m \cdot s^{-2}} = 36.45\; \rm m\end{aligned}.

In other words, the maximum height that this rocket attained would be 36.45\; \rm m.

Again, assume that the air resistance on this rocket is negligible. The rocket would return to the ground along the same path, and would cover a total distance of 2\times 36.45\; \rm m = 72.9\; \rm m.

7 0
3 years ago
The greatest ocean depths on the earth are found in the marianas trench near the philippines. calculate the pressure due to the
tensa zangetsu [6.8K]
First, let us derive our working equation. We all know that pressure is the force exerted on an area of space. In equation, that would be: P = F/A. From Newton's Law of Second Motion, force is equal to the product of mass and gravity: F = mg. So, we can substitute F to the first equation so that it becomes, P = mg/A. Now, pressure can also be determined as the force exerted by a fluid on an area. This fluid can be measure in terms of volume. Relating volume and mass, we use the parameter of density: ρ = m/V. Simplifying further in terms of height, Volume is the product of the cross-sectional area and the height. So, V = A*h. The working equation will then be derived to be:

P = ρgh

This type of pressure is called the hydrostatic pressure, the pressure exerted by the fluid over a known height. Next, we find the literature data of the density of seawater. From studies, seawater has a density ranging from 1,020 to 1,030 kg/m³. Let's just use 1,020 kg/m³. Substituting the values and making sure that the units are consistent:

P = (1,020 kg/m³)(9.81 m/s²)(11 km)*(1,000 m/1km)
P = 110,068,200 Pa or 110.07 MPa
6 0
3 years ago
Find the current in the 12 ohm resistor.
disa [49]

Answer:

1.5 A

Explanation:

V =I.R

18 = I × 12

I = 18/12

= 3/2 = 1.5 A

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3 years ago
Josie sees lightning off in the distance. A few seconds later she hears thunder. What can Josie conclude?
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