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Novay_Z [31]
3 years ago
11

A centripetal force of 1,400 newtons acts on a car rounding a curve with a radius of 150 meters. If the car has a mass of 2,100

kilograms, find its velocity, in meters per second.
Physics
1 answer:
Kruka [31]3 years ago
7 0

In circular motion, the centripetal force is  v²/R , and the
centripetal force is (mass) x (acceleration)  =  M v²/R .

                                              1400  =  2100 v² / 150

Divide each side by  2100 :   2/3     =          v² / 150

Multiply each side by  150 :  100     =         v²

Square root each side:           v       =  10 m/s .

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A +71 nC charge is positioned 1.9 m from a +42 nC charge. What is the magnitude of the electric field at the midpoint of these c
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Answer:

The net Electric field at the mid point is 289.19 N/C

Given:

Q = + 71 nC = 71\times 10^{- 9} C

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To find the magnitude of electric field at the mid point,

Electric field at the mid-point due to charge Q is given by:

\vec{E} = \frac{Q}{4\pi\epsilon_{o}(\frac{d}{2})^{2}}

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\vec{E} = 708.03 N/C

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Electric field at the mid-point due to charge Q' is given by:

\vec{E'} = \frac{Q'}{4\pi\epsilon_{o}(\frac{d}{2})^{2}}

\vec{E'} = \frac{42\times 10^{- 9}}{4\pi\8.85\times 10^{- 12}(\frac{1.9}{2})^{2}}

\vec{E'} = 418.84 N/C

Now,

The net Electric field is given by:

\vec{E_{net}} = \vec{E} - \vec{E'}

\vec{E_{net}} = 708.03 - 418.84 = 289.19 N/C

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