A coin of mass .005 kg dropped from a height of 3 m. How much potential energy does it have right before it hits the ground? Ass
ume there is no air resistance. Acceleration due to gravity is g=9.8 m/s2
1 answer:
Answer:
0 J
Explanation:
Gravitational potential energy is:
PE = mgh
where m is mass, g is acceleration due to gravity, and h is the height.
Right before the coin hits the ground, its height above the ground is 0 m, so the potential energy is:
PE = mgh
PE = (0.005 kg) (9.8 m/s²) (0 m)
PE = 0 J
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a)1500N
b)153.06kg
Explanation:
F = ma
g(moon) = is the acceleration due to gravity on the moon
g(earth) is the acceleration due to gravity on the earth
g(moon) = 1/6g(earth)
g(earth) =6g(moon)
F(gearth) = mg(earth)
= m 6g(moon)
= 6 × 250
= 1500N
b) F(gearth) = mg(earth)
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= 153.06kg
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