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3 years ago

Math gram question please help thanks

Mathematics

1 answer:

mezya [45]3 years ago

7 0

Density is calculated by mass divided by volume.
This would be 60/24 (60 grams mass divided by 24 cm^3 volume)
60/24 = 2.5
This means the answer is B. 2.5 g/cm^3

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Point M is the midpoint of CD¯¯¯¯¯¯¯¯. C has coordinates of (-1, 1) and D has coordinates of (5,-5). What are the coordinates of

snow_lady [41]

Answer:

The answer is (2,-2)

7 0

2 years ago

If there are twice as many bicycles as scooters and there are 945 vehicles in total. How many bicycles and scooters are there in

alexandr402 [8]

Answer:

Bicycles = 315

Scooters = 630, basic mathematics. The most effective method for these questions is substitution. But I might have intermingled them so double check

3 0

3 years ago

Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"

vampirchik [111]

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h$

Employ a standard trick used in proving the chain rule:

$\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h$

The limit of a product is the product of limits, i.e. we can write

$\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)$

The rightmost limit is an exercise in differentiating $\sqrt x$ using the definition, which you probably already know is $\dfrac1{2\sqrt x}$ .

For the leftmost limit, we make a substitution $y=\sqrt x$ . Now, if we make a slight change to $x$ by adding a small number $h$ , this propagates a similar small change in $y$ that we'll call $h'$ , so that we can set $y+h'=\sqrt{x+h}$ . Then as $h\to0$ , we see that it's also the case that $h'\to0$ (since we fix $y=\sqrt x$ ). So we can write the remaining limit as

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}$

which in turn is the derivative of $\tan y$ , another limit you probably already know how to compute. We'd end up with $\sec^2y$ , or $\sec^2\sqrt x$ .

So we find that

$\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}$

7 0

3 years ago

10) Solve the equation.<br> - 3(2x + 6) + 81 = 34 - 43

Maslowich

Answer:

x = 8

Step-by-step explanation:

-6x + 63 = -9

-6x = -72

x = 8

5 0

3 years ago

Read 2 more answers

The graph for the function f(x) is shown. Which of the following ordered pairs are a

never [62]

Is this Calvert learning

6 0

2 years ago