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harkovskaia [24]
3 years ago
11

Please answer to receive ten points. I'll vote who answers first the brainliest if its correct. 

Mathematics
1 answer:
beks73 [17]3 years ago
3 0

The distance between points P_1(x_1,y_1) and P_2(x_2,y_2) can be calculated using formula

P_1P_2=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

1.

AB=\sqrt{(-7-(-11))^2+(8-4)^2}=\sqrt{16+16}=\sqrt{32}=4\sqrt{2}\approx 5.657.

2.

AC=\sqrt{(-4-(-11))^2+(4-4)^2}=\sqrt{49+0}=\sqrt{49}=7.

3.

CB=\sqrt{(-7-(-4))^2+(8-4)^2}=\sqrt{9+16}=\sqrt{25}=5.

Then

P_{ABC}=5.657+7+5=17.657\approx 17.7

Answer: correct choice is C.

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Verdich [7]

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<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

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