How fast does a 3 kg rocket accelerate if a force of 140 N is applied?
1 answer:
<h3>
Answer:</h3>
46.67 m/s²
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of a rocket = 3 kg
- Force applied = 140 N
we are supposed to calculate the acceleration of the rocket;
- We are going to use the second Newton's law of motion;
- According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.
- This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.
Therefore;
F = Ma
In this case;
Rearranging the formula
a = F ÷ m
= 140 N ÷ 3 kg
= 46.67 m/s²
Thus, the acceleration of the rocket is 46.67 m/s²
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Answer:
a. 150 g/L
b. 75 g
c. 120 mL
Explanation:
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b. 33g/0.22L=150 g/L
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c. 0.22L/33g=0.006667L/g
0.006667L/g*18g=0.12L
0.12L*1000=120mL
Answer:
W=f×d
w=45×27
w=1215 j.............
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