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olga2289 [7]
4 years ago
14

How fast does a 3 kg rocket accelerate if a force of 140 N is applied?

Physics
1 answer:
elixir [45]4 years ago
3 0
<h3>Answer:</h3>

46.67 m/s²

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of a rocket = 3 kg
  • Force applied = 140 N

we are supposed to calculate the acceleration of the rocket;

  • We are going to use the second Newton's law of motion;
  • According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.
  • This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.

Therefore;

F = Ma

In this case;

Rearranging the formula

a = F ÷ m

  = 140 N ÷ 3 kg

  = 46.67 m/s²

Thus, the acceleration of the rocket is 46.67 m/s²

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Answer:

The weight of the wheelbarrow and the road is 784 N and the force required to lift the wheelbarrow is 784 N.

Explanation:

Given that,

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The weight of an object is given by :

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3 years ago
) determine the density of a 32.5 g metal sample that displaces 8.39 ml of water.
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3 0
4 years ago
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8 0
3 years ago
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Re-arranging the formula, we get:
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