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Art [367]
3 years ago
12

a student lift a 25kg mass at vertical distance of 1.6m in a time of 2.0 seconds. a. Find the force needed to lift the mass (in

N ). b. Find the work done by the student (in J). c. Find the power exerted by the student (in W)
Physics
1 answer:
zhannawk [14.2K]3 years ago
5 0

Answer:

a. F = 245 Newton.

b. Workdone = 392 Joules.

c. Power = 196 Watts

Explanation:

Given the following data;

Mass = 25kg

Distance = 1.6m

Time = 2secs

a. To find the force needed to lift the mass (in N );

Force = mass * acceleration

We know that acceleration due to gravity is equal to 9.8

F = 25*9.8

F = 245N

b. To find the work done by the student (in J);

Workdone = force * distance

Workdone = 245 * 1.6

Workdone = 392 Joules.

c. To find the power exerted by the student (in W);

Power = workdone/time

Power = 392/2

Power = 196 Watts.

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Answer:

What kind of languege is this please?

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2 years ago
I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?
Ulleksa [173]

Answer:

<em>B. 68.6m</em>

Explanation:

<u>Free Fall Motion </u>

When a body is left to move in the air with no friction, the motion is ruled only by the force of gravity. The vertical distance a body travels in the air after a time t is .

\displaystyle y=\frac{gt^2}{2}

We know the egg takes 3.74 seconds to reach the ground. The height it was launched from is

\displaystyle y=\frac{(9.8)(3.474)^2}{2}

\displaystyle y=68.54\ m

The closest correct option is

B. 68.6m

5 0
3 years ago
Fill in the term that completes the statement. The north and south poles of a magnetic field produced by an electromagnet will s
Minchanka [31]

Answer:

when the direction of the Current changes.

Explanation:

Electromagnet refers to an iron ore wrapped around with a coil of wire, in presence of electric current. As it acts like a magnet, when current is passed through it.

The north & south poles of magnetic fields produced by such magnet, change with direction of current passed through it.

6 0
3 years ago
Read 2 more answers
The first artificial satellite to orbit the Earth was Sputnik I, launched October 4, 1957. The mass of Sputnik I was 83.5 kg, an
9966 [12]

Answer:

-4.941*10^8J.

Explanation:

To solve this exercise it is necessary to take into account the concepts related to gravitational potential energy, as well as the concept of perigee and apogee of a celestial body.

By conservation of energy we know that,

\Delta U = \Delta_{perogee}-\Delta_{Apogee}

Where,

U= \frac{-GmM_e}{r}

Replacing

\Delta U = \frac{-GmM_e}{r_p}- \frac{-GmM_e}{r_a}

\Delta U = GmM_e (\frac{1}{r_A}-\frac{1}{r_p})

Our values are given by,

m = 85.5Kg

M_e = 5.97*10^{24}Kg

r_A = 7330Km

r_p = 6610Km

G = 6.67*10^{-11}Nm^2/Kg^2

Replacing at the equation,

\Delta U = (6.67*10^{-11})(85.5)(5.97*10^{24}) (\frac{1}{7330}-\frac{1}{6610})

\Delta U = -4.941*10^8J

Therefore the Energy necessary for Sputnik I as it moved from apogee to perigee was -4.941*10^8J.

4 0
3 years ago
An electromagnetic wave has a frequency of 4.0 x 1018 Hz. What is the
trapecia [35]

Answer: D

Wavelength λ = 7.5 × 10^-11 m

Explanation:

You are given the frequency of an electromagnetic wave to be:

F = 4.0 x 1018 Hz. And the speed of light C to be

C = 3 × 10^8 m/s

From wave speed formula:

Wave speed is the product of waves frequency and wavelength. That is,

V = fλ

Where

f = frequency

λ = wavelength

V = C = speed of light

Substitute the values of the parameters into the formula

C = fλ

3 × 10^8 = 4 × 10^18 × λ

Make λ the subject of formula

λ = (3×10^8)/(4×10^18)

λ = 7.5 × 10^-11 m

Therefore, the wavelength of the wave is 7.5 × 10^-11 m

8 0
3 years ago
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