Ask question

Ask question

All categories

3 years ago

8

Running on a treadmill is slightly easier than running outside because there is no drag force to work against. suppose a 60 kg r

unner completes a 5.0 km race in 16 minutes.

1 answer:

professor190 [17]3 years ago

7 0

So it will take 5 minutes if a person running on a treadmill so it will be easy.

You might be interested in

By what factors does the speed of the elctron exceed that of the proton?<br>

____ [38]

Answer:

» An electron is lighter than a proton.

<u>explanation</u><u>:</u>

${ = \: \sf{an \: electron \: has \: formula \: \: }}{ \bf{ {}^{0}_{ - 1}e }}$

hence it's mass number is zero

${ = \: \sf{an \: electron \: is \: helium \: particle \: \: }}{ \bf{ {}^{4} _{2}He }}$

hence it's mass number is 4

<u>Therefore</u><u>,</u><u> </u><u>proton</u><u> </u><u>is</u><u> </u><u>heavier</u><u> </u><u>than</u><u> </u><u>electron</u>

» An electron has a small charge magnitude than a proton.

<u>Explanation</u><u>:</u>

An electron has charge of -1 while proton has charge of +2, therefore electron is less deflected by any energetic fields than a proton

8 0

3 years ago

Consider and mass of a material

Leni [432]

Answer:Density is the mass of an object divided by its volume. Density often has units of grams per cubic centimeter (g/cm3). ... You probably have an intuitive feeling for density in the materials you use often. For example, sponges are low in density; they have a low mass per unit volume.

Explanation:

3 0

3 years ago

A 2.02 nF capacitor with an initial charge of 4.55 µC is discharged through a 1.22 kΩ resistor. (a) Calculate the current in the

Mandarinka [93]

Answer:

a) 0.048A

b) 0.18µC

c) 1.85A

Explanation:

The discharged current of the capacitor as a function of time is given by:

$i=\frac{q_o}{RC}*e^{-\frac{t}{\tau}}\\where:\\\tau=RC\\$

$\tau=1.22*10^3*2.02*10^{-9}\\\tau=2.46*10^{-6}s$

a)

$i=\frac{4.55\µC}{2.46\µs}*e^{-\frac{9\µs}{2.46\µs}}\\\\i=0.048A$

b)

$q=q_o*e^{-\frac{t}{\tau}}$

$q=4.55\µC*e^{-\frac{8\µs}{2.46\µs}}\\q=0.18\µC$

c) the maximum current occurs when t=0

$i=\frac{4.55\µC}{2.46\µs}*e^{-\frac{0\µs}{2.46\µs}}\\\\i=1.85A$

6 0

3 years ago

In a police ballistics test, a 10.0-g bullet moving at 300 m/s is fired into a 1.00-kg block at rest. The bullet goes through th

natta225 [31]

Answer:

Speed of block after the bullet emerges = 1.5 m/s

Explanation:

Here momentum is conserved.

Initial momentum = Final momentum.

Mass of bullet = 10 g = 0.01 kg

Initial Velocity of bullet = 300 m/s

Mass of block = 1 kg

Initial Velocity of block = 0 m/s

Final Velocity of bullet = 50% of initial velocity. = 150 m/s

We need to find final velocity of block. Let it be v

We have

Initial momentum = 0.01 x 300 + 1 x 0 = 3 kg m/s

Final momentum = 0.01 x 150 + 1 x v = 1.5 + v

Equating

3 = 1.5 + v

v = 1.5 m/s

Speed of block after the bullet emerges = 1.5 m/s

3 0

3 years ago

In prokaryotic and eukaryotic cells the amount of water in the cell is kept at a steady state. the organelles through which wate

ipn [44]

Cell membrane. This is where chemicals enter and exit the cell.

5 0

3 years ago