1) gradient of line = Δ y ÷ Δ x
= (5 -2) ÷ (3 - (-6))
= ¹/₃
using the point-slope form (y-y₁) = m(x-x₁)
using (3,5)
(y - 5) = ¹/₃ (x -3)
y - 5 = ¹/₃x - 1
⇒ <span> y = ¹/₃ x + 4 [OPTION D]
</span>2) y = 2x + 5 .... (1)
<span> </span>y = ¹/₂ x + 6 .... (2)
by substituting y in (1) for y in (2)
2x + 5 = ¹/₂ x + 6
³/₂ x = 1
x = ²/₃
by substituting found x (2)
y = ¹/₂ (²/₃) + 6
y = ¹⁹/₃
∴ common point is (²/₃ , ¹⁹/₃) thus answer is FALSE [OPTION B]
3) Yes [OPTION A]
This is because the both have a gradient of 5 and if they have the same gradient then that means that the two lines are parallel to each other.
4) No [OPTION B]
Two lines are perpendicular if their gradients multiply to give - 1 and as such one is the negative reciprocal of the other. Since both gradients are ¹/₂ then they are actually parallel and not perpendicular.
Answer:
96 in 8th grade
Step-by-step explanation:
You times 24 by four to get 96. Then to check your answer you need to do 25%96 and you will get 24 to show that you are right.
16 ounces in a pound.
24 oz= 1.5 ibs.
Added to 10 ibs.
Now has 11.5 ibs.
R(x)= 11.5 - x
<span>sin 90° = 1
</span>
cos 0° = 1
There's a simple formula : <em>sin θ = cos (90°- θ)</em> or <em>cos θ = sin (90°- θ) </em>
So : cos 0° = sin (90° - 0°) = sin 90° = 1
