A 1.5m wire carries a 7 A current when a potential difference of 54 V is applied. What is the resistance of the wire?
2 answers:
<h2>Answer:</h2>
The resistance of wire will be 7.71 Ohms
<h2>Step-by-step explanation:
</h2>
According to Ohm's Law
V = IR
R= V/ I
Putting the value
R = 54 / 7
R = 7.71 Ohms
Answer:
R = 7.71 ohms
Step-by-step explanation:
By ohm's law: R= V/I
where, R = resistance of wire, V = potential difference, I = electric current
Given: V = 54 and I = 7 A
Plug in the above values in the ohm's law, we get
R = 54 V/7 A
R = 7.71 ohms
Hope this will helpful.
Thank you.
You might be interested in
If you count the crosses, there are 4 of them
4 Runners ran 1/3 of a mile
4 runners, D
Hope this helps
Answer:
Simplify ----2√45 + 3√3 + 2√3
A~ --18√5 + 5√3
B~ --6√5 + 6√3
C~ --2√5 + 6√3
<u>D~ --6√5 + 5√3</u>
Step-by-step explanation:
[tex]-2\sqrt{45}+3\sqrt{3} +2\sqrt{3} =-2\sqrt{45} + 5\sqrt{3} =-6\sqrt{5} + 5\sqrt{3}[/tex
Answer:
y=-1/3x+3
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
The coefficient is the number before the variable. Therefore 2 is the coefficient of variable q.
