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3 years ago

A 1.5m wire carries a 7 A current when a potential difference of 54 V is applied. What is the resistance of the wire?

Mathematics

2 answers:

ipn [44]3 years ago

7 0

<h2>Answer:</h2>

The resistance of wire will be 7.71 Ohms

<h2>Step-by-step explanation: </h2>

According to Ohm's Law

V = IR

R= V/ I

Putting the value

R = 54 / 7

R = 7.71 Ohms

borishaifa [10]3 years ago

6 0

Answer:

R = 7.71 ohms

Step-by-step explanation:

By ohm's law: R= V/I

where, R = resistance of wire, V = potential difference, I = electric current

Given: V = 54 and I = 7 A

Plug in the above values in the ohm's law, we get

R = 54 V/7 A

R = 7.71 ohms

Hope this will helpful.

Thank you.

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Step-by-step explanation:

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2 years ago

Can you guys please do both with the work please and thank you if you actually do it

salantis [7]

Answer:

7. 29 cm

8. equation: 61 = (x) +(2x -7) +(3x +2); sides 11, 15, 35

Step-by-step explanation:

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Substituting the known values, we have ...

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L = 2w -3 = 2(16) -3 = 29

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<em>Comment on problem 8</em>

You will notice that the side lengths do not satisfy the triangle inequality: the sum of the short sides is not greater than the long side. <em>These side lengths cannot form a triangle</em>. Cute algebra, but <em>bad geometry</em>.

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