4 years ago

A 1.5m wire carries a 7 A current when a potential difference of 54 V is applied. What is the resistance of the wire?

Mathematics

2 answers:

ipn [44]4 years ago

7 0

<h2>Answer:</h2>

The resistance of wire will be 7.71 Ohms

<h2>Step-by-step explanation: </h2>

According to Ohm's Law

V = IR

R= V/ I

Putting the value

R = 54 / 7

R = 7.71 Ohms

borishaifa [10]4 years ago

6 0

Answer:

R = 7.71 ohms

Step-by-step explanation:

By ohm's law: R= V/I

where, R = resistance of wire, V = potential difference, I = electric current

Given: V = 54 and I = 7 A

Plug in the above values in the ohm's law, we get

R = 54 V/7 A

R = 7.71 ohms

Hope this will helpful.

Thank you.

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