Answer:
- <em><u>B) Bill's wagon is moving 4 times faster than Tom's. </u></em>
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Explanation:
The motion of the wagons is determined by the net force that acts upon them, according to Newton's second law of motion:
- Force = mass × acceleration ⇒ acceleration = Force / mass
From your data, you can fill this table to compare the accelerations:
Bill's wagon Tom's wagon
mass (lb) 10 20
force 2F F
acceleration 2F/10 F/20
Find the ratio between both accelarations:
- Bill's wagon acceleration / Tom's wagon acceleration
- (2F/10) / (F/20) = (2 × 20 / 10 ) = 4
Meaning that the acceleration of Bill's wagon is 4 times the acceleration of Tom's wagon.
Assuming, that both wagons start from rest, you can obtain the speeds from the kinematic equation for uniformly accelerated motion:
- Speed = acceleration × time, V = a × t.
Call the acceleration of Tom's wagon X, then the acceleration of Bill's wagon will be 4X.
So, depending on the time, using V = a × t, the speeds will vary:
t (s) 1 2 3 4
Speed Tom's wagon X 2X 3X 4X
Speed Bill's wagon 4X 8X 12X 16X
Concluding that Bill's wagon is moving 4 times faster than Tom's (option B).
I don't know what model you're referring to so I can't answer the question. However, upon researching, I found a similar problem. I posted it as an attached picture. Looking at the model, the amount of grams a herbivore eat each day corresponds to the arrow pointing inwards. Since the label says 4.0 g,
<em>the answer is 4 g per day</em>.
20 molecules minus ten degrees equals 1001
Answer:
4.12 moles
Explanation:
We can solve this problem with the Ideal Gases Law.
P . V = n . R . T
In our first case we have:
P = 2.3 atm
V = 32.8 L
n = 2.98 moles
T → 35°C + 273 = 308K
Let's replace data for the second case:
2.3 atm . 45.3L = n . 0.082 . 308K
n = (2.3 atm . 45.3L) / (0.082 L.atm/mol.K . 308K)
n = 4.12 moles
