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balandron [24]
3 years ago
8

What is the molar mass of water in the hydrate? FeSO4 • 7H2O

Chemistry
1 answer:
Rainbow [258]3 years ago
5 0
M=7M(H₂O)

M=7*18.015 g/mol = 126.105 g/mol
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kupik [55]

Answer:

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ΔH rxn = 2 ΔHºf NH3 - ΔHºf N2H4

but we also know that the ΔH rxn is calculated by accounting   the sum of number of bonds formed and bonds broken as follows:

ΔH rxn = 6H (N-H) + 4 (N-H) + 2H (H-H)  

where H is the bond enthalpy .When bonds are broken H is positive, and negative when formed,  in the product there are 6 N-H bonds , and in the reactants 4 N-H and 1 H-H bonds).

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ΔHºf (NH3) = -46 kJ/mol

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H(N-N) = 162.6 kJ

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