Answer:

Step-by-step explanation:
<h3>Arithmetic sequence:</h3>

6th term is 14 ⇒ 
a + (6 - 1)d = 14
a + 5d = 14 --------------(I)
14th term is 6 ⇒
a + (14-1)d = 6
a + 13d = 6 ----------------(II)
Subtract equation (II) from equation(I)
(I) a + 5d = 14
(II) a + 13d = 6
<u>- - -</u>
-8d = 8
d = 8 ÷(-8)

Plugin d = -1 in equation (I)
a + 5(-1) = 14
a -5 = 14
a = 14 + 5
20th term:

= 19 - 19

Answer:
the answer is x because its small
Solution:
we are given that
A jury pool consists of 50 potential jurors.
Wee have been asked to find the number of ways can a jury of 12 be selected.
As we know from the concept of combination that r person can be selected out of n in ncr ways. where

Now substitute the values we get

Hence the required number of ways is 121399651100
Answer:
8?
Step-by-step explanation:
I am not positive but I think the answer might be 8?