Answer:
=x(x-1) +3x
= x^2-x+3x
=x^2 +2x
=x(x+2)
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
From any point (x, y) on the parabola the focus and directrix are equidistant
Using the distance formula
= | y + 1 |
Squaring both sides
(x + 5)² + (y - 5)² = (y + 1)^2 , that is
(y + 1)² = (x + 5)² + (y - 5)² ← subtract (y - 5)² from both sides
(y + 1)² - (y - 5)² = (x + 5)² ← expand left side and simplify
y² + 2y + 1 - y² + 10y - 25 = (x + 5)²
12y - 24 = (x + 5)² ← factor left side
12(y - 2) = (x + 5)² ← divide both sides by 12
y - 2 = 
(x + 5)² ← add 2 to both sides
y = (x + 5)² + 2
or
f(x) = (x + 5)² + 2 → D
Answer:
The one you are on, f(x+2)+4
Step-by-step explanation:
First, we can see by the 0 point that it is just moved up by 4 and not left or right any, so we want to see how it has changed without the +4.
in g(x) the x changes by two, 0 to 2, and the y changes by one, 4 to 5.
Hopefully you can tell what the function being manipulated is. It is x^3 so if we write that instead of f(x) in the answers the first one for instance would be (x/3)^3-4. (let me know if that doesn't make sense)
SInce we already know it's being moved up by 4, we know it's one of those with +4 at the end. It's easy enough to guess and check, but the process to find the answer is pretty easy. We also know that at 2, the change is 1. So without the +4 at the end, what would let us change 8 to 1? dividing it by 8, which is also 2^3. so that means (2/2)^3. So the answer is we want f(x/2) witht he +4 at the end.
Hopefully that made sense, I'd be happy to explain further if you need though
