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eduard
1 year ago
5

The measure of an angle’s supplement is 76° less than the measure of the angle. Find the measures of the angle and its supplemen

t.
Mathematics
1 answer:
geniusboy [140]1 year ago
4 0

Answer:

The measure of an angle's supplement is 76 less than the measure of the angle. Find the measure of the angle and its supplement. Hence, the angle's measure is 128.

Step-by-step explanation:

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Pls, can someone help me with this problem?
ExtremeBDS [4]

Answer:

0.\overline{33}

Step-by-step explanation:

If you divide number 1 by number 3, you will notice that number 3 will constantly repeat at the decimal part.

So, the answer is 0.\overline{33}.

5 0
2 years ago
Find the percent of error if the estimate is $230 and the actual amount is $245. round to the nearest whole percent.
qwelly [4]

Percentage error = 245-230/245 * 100 = 15/245 * 100 = 6.12%

After rounding off, it would be 6%

5 0
2 years ago
1. M is the midpoint of LN and O is the midpoint of NP.
Reptile [31]
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4. 
The line would be 
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5. 
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
5 0
2 years ago
Solve for a side in right triangles (soh cah toa)
nevsk [136]
Cos(35) = x/6
or 6 * cos(35) = x
3 0
3 years ago
What is the y-intercept of the function f(x) = _2/9×+1/3​
Leokris [45]

Answer:The y intercept is (0.0.333)

Step-by-step explanation:

5 0
3 years ago
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