Attached is the MOT of NO molecule.
1. Bond order is calculated is

In present case, number of e- in bonding orbital = 6
number of e- in anti-bonding orbital = 1
∴ Bond-order =

= 2.5
2. From the attached figure, it can be seen that NO has one unpaired electron in π* orbital.
Inertia is the answer to this question
They have the same amounts of electrons
Answer:
ik ppl sy no links but https://courses.lumenlearning.com/cheminter/chapter/the-ph-scale/
Explanation: it should help you
<span> Mg(OH)2(s) + 2HCl(aq) yield MgCl2(aq) + 2H2O(l)
grams HCl required = (50.6 grams Mg(OH)2) * (1 mol Mg(OH)2 / 58.3197 grams Mg(OH)2) * (2 mol HCl / 1 mol Mg(OH)2) * (36.453 grams HCl / 1 mol HCl) = 63.26 grams HCl required
Since there are only 45.0 grams HCl, then HCl is the limiting reactant.
theoretical yield MgCl2 = (45.0 grams HCl) * (1 mol HCl / 36.453 grams HCl) * (1 mol MgCl2 / 2 mol HCl) * (95.211 grams MgCl2 / 1 mol MgCl2) = 58.6 grams MgCl2 </span>