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Anika [276]
3 years ago
10

PLS HELP ME ASAP FOR 14!! (SHOW WORK!!) + LOTS OF POINTS!! *GIVING THANKS!*

Mathematics
1 answer:
ale4655 [162]3 years ago
7 0
I can't exactly see those. Sorry I can't help you
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Find S5 for a geometric series for which a1=81 and r=1/9.
Minchanka [31]

ANSWER

S_5=91\frac{10}{81}




EXPLANATION


The sum of the first n terms of a geometric sequence is given by;


S_n=\frac{a_1(1-r^n)}{1-r} ,-1


Where n, is the number of terms and a_1 is the first term.


When n=5, we have a_1=81, we get;


S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}


S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}


S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}




S_5=\frac{7381}{81}


S_5=91\frac{10}{81}




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3 years ago
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Andrew [12]

you multiply -10 and nine and you get -90 hope this helps.

Step-by-step explanation:

6 0
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