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Firdavs [7]
3 years ago
14

What is the perimeter and area of length is 13 inches in width is 9.5 inches

Mathematics
2 answers:
love history [14]3 years ago
7 0

Answer:

perimeter = 45 in.

area = 123.5 in.^2

Step-by-step explanation:

I assume this is a rectangle.

L = 13 in.

W = 9.5 in.

perimeter = 2(L + W) = 2(13 in. + 9.5 in.) = 2(22.5 in.) = 45 in.

area = LW = 13 in. * 9.5 in. = 123.5 in.^2

gregori [183]3 years ago
7 0

Answer:

I think the perimeter is 45in and the area is 123.5in^2

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<em>First, let's start by finding the slope of your new line. We know that it needs to have the same slope as 5x+4y=2, because parallel lines have the same slopes. To do that, we need to put the equation into slope-intercept form (y=mx+b), which means we need to isolate the "y."  </em>

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<em>  5x+4y=2 </em>

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<em>Now, we know that our slope, m , is going to be -(5/4).  </em>

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<em>Next, we are going to use our slope, -(5/4), and point, (7, 5), to find the b-value (y-intercept) of your new line. Let's plug in what we know: </em>

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<em>y = 5 </em>

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<em>m = -(5/4) </em>

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<em>y=mx+b </em>

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<em>5=(-5/4)(7) + b  -> I plugged in what we knew for y, m, and x.  </em>

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<em>5 = -(35/4) + b  -> I multiplied the numbers in the numerator (5 x 7) to get 35/4 </em>

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<em>Answer:  </em>

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