1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lesya692 [45]
3 years ago
13

What is the quotient (x3 – 3x2 + 5x – 3) ÷ (x – 1)?

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer:

  1. x^2 -2x +3
  2. x^2 +2x +3

Step-by-step explanation:

The quotient in each case can be found by any of several means, including synthetic division (possibly the easiest), polynomial long division, or graphing.

1. The graph shows you the quotient is (x-1)^2 +2 = x^2 -2x +3.

2. The graph shows you the quotient is (x+1)^2 +2 = x^2 +2x +3.

You might be interested in
How can the Pythagorean theorem be used to find the exact values of certain "special angles"?​
Reptile [31]

In a 45-45-90 triangle, the two legs are congruent. Let's call them x. The hypotenuse is equal to 1 as we're using the unit circle. The hypotenuse of the triangle is the same as the radius of the unit circle.

a = x

b = x

c = 1

Use those values in the Pythagorean theorem to solve for x.

a^2 + b^2 = c^2

x^2 + x^2 = 1^2

2x^2 = 1

x^2 = 1/2

x = sqrt( 1/2 )

x = sqrt(1)/sqrt(2)

x = 1/sqrt(2)

x = sqrt(2)/2 ... rationalizing the denominator

So this right triangle has legs that are sqrt(2)/2 units long. Once we know the legs of the triangle, we can divide them over the hypotenuse to find the sine and cosine values.

sin(angle) = opposite/hypotenuse

sin(45) = (sqrt(2)/2) / 1

sin(45) = sqrt(2)/2

and

cos(angle) = adjacent/hypotenuse

cos(45) = (sqrt(2)/2) / 1

cos(45) = sqrt(2)/2

------------------------------------------------------

For a 30-60-90 triangle, we would have

a = 1

b = x

c = 2

so,

a^2+b^2 = c^2

1^2+x^2 = 2^2

1+x^2 = 4

x^2 = 4-1

x^2 = 3

x = sqrt(3)

The missing leg is sqrt(3) units long.

Once we know the three sides of the 30-60-90 triangle, you should be able to see that

sin(30) = 1/2

sin(60) = sqrt(3)/2

cos(30) = sqrt(3)/2

cos(60) = 1/2

3 0
3 years ago
Read 2 more answers
Laura can weed the garden in 1 hour and 20 minutes and her husband can weed it in 1 hour and 30 minutes. How long will they take
Harrizon [31]
<h2>Hello!</h2>

The answer is:

It will take 42.35 minutes to weed the garden together.

<h2>Why?</h2>

To solve the problem, we need to use the given information about the rate for both Laura and her husband. We know that she can weed the garden in 1 hour and 20 minutes (80 minutes) and her husband can weed it in 1 hour and 30 minutes (90 minutes), so we need to combine both's work and calculate how much time it will take to weed the garden together.

So, calculating we have:

Laura's rate:

\frac{1garden}{80minutes}

Husband's rate:

\frac{1garden}{90minutes}

Now, writing the equation we have:

Laura'sRate+Husband'sRate=CombinedRate

\frac{1}{80}+\frac{1}{90}=\frac{1}{time}

\frac{1*90+1*80}{7200}=\frac{1}{time}

\frac{170}{7200}=\frac{1}{time}

\frac{17}{720}=\frac{11}{time}

\frac{17}{720}=\frac{1}{time}

\frac{17}{720}*time=1

time=1*\frac{720}{17}=42.35

Hence, we have that it will take 42.35 minutes to weed the garden working together.

Have a nice day!

8 0
4 years ago
Use the table to identify the values of p and q that should be used to factor x^2+9x-10 as (x+p)(x+q)
likoan [24]
X^2 + 9x -10 = (x -1)(x +10) = (x +(-1)) (x + 10)
p = -1 and q  = 10
answer is A.
5 0
3 years ago
Read 2 more answers
Patricia is 5 years older than Wyatt. The sum of their ages is 61. How old are Patricia and Wyatt?
baherus [9]

Answer

w+(w+5)=61

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
4&gt; Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o
harina [27]

Answer:

y=3e^{-4t}

Step-by-step explanation:

y''+5y'+4y=0

Applying the Laplace transform:

\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0

With the formulas:

\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)

\mathcal{L}[y']=s\mathcal{L}[y]-y(0)

\mathcal{L}[x]=L

s^2L-3s+5sL-3+4L=0

Solving for L

L(s^2+5s+4)=3s+3

L=\frac{3s+3}{s^2+5s+4}

L=\frac{3(s+1)}{(s+1)(s+4)}

L=\frac3{s+4}

Apply the inverse Laplace transform with this formula:

\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}

y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}

7 0
3 years ago
Other questions:
  • Grapes were priced at 3 pounds for$5.28 what was the priced per pound
    8·2 answers
  • Explain why the product of any four consecutive integers is divisible by 24.<br> ...?
    15·1 answer
  • You have two jobs. One job pays $7 per hour and the other pays $8.25 per hour. You worked 22 hours total last week and earned $1
    11·1 answer
  • Classify the following triangle. Check all that apply.
    6·2 answers
  • The wavelength of the color red is about 6.5 × 10^−9 m. The wavelength of the color blue is about 4.75 × 10^−9 m. Show that the
    14·1 answer
  • 5 women each ate 3 mangoes everyday. how many mangoes did they eat in 6 days?
    9·2 answers
  • Professional football field is 160 feet wide what's the width of the field in yards
    8·1 answer
  • Find the value of the d. 2d -5 = 17
    14·1 answer
  • Find the Product: (2x+3) (x-4)​
    8·2 answers
  • ASP PLZ
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!